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PAT 甲级 1132 Cut Integer

https://pintia.cn/problem-sets/994805342720868352/problems/994805347145859072 Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 an…

PAT甲级——A1132 Cut Integer

Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A…

PAT Advanced 1132 Cut Integer (20) [数学问题-简单数学]

题目 Cutting an integer means to cut a K digits long integer Z into two integers of (K/2) digits long integers A and B. For example, afer cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of…

PAT 1132 Cut Integer

1132 Cut Integer (20 分)   Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be de…

PAT 1132 Cut Integer[简单]

1132 Cut Integer(20 分) Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devid…

pat 1132 Cut Integer（20 分）

1132 Cut Integer(20 分) Cutting an integer means to cut a K digits lone integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devid…

1132. Cut Integer (20)

Cutting an integer means to cut a K digits long integer Z into two integers of (K/2) digits long integers A and B. For example, after cutting Z = 167334, we have A = 167 and B = 334. It is interesting to see that Z can be devided by the product of A…

1132 Cut Integer

题意:略. 思路:注意除数可能为0的情况,不然会导致浮点错误. 代码: #include <iostream> #include <string> using namespace std; int main() { int n; string str; cin>>n; while(n--){ cin>>str; ,str.size()/); ,str.size()/); int a=stoi(s1),b=stoi(s2),val=stoi(str); &am…

【PAT甲级】1113 Integer Set Partition (25分)

题意: 输入一个正整数N(2<=N<=1e5),接着输入N个正整数,将这些数字划分为两个不相交的集合,使得他们的元素个数差绝对值最小且元素和差绝对值最大. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL…

【PAT甲级】1103 Integer Factorization (30 分)

题意: 输入三个正整数N,K,P(N<=400,K<=N,2<=P<=7),降序输出由K个正整数的P次方和为N的等式,否则输出"Impossible". //找到最大可能的整数pos后从大到小爆搜,sample 1给的输出好像不是最大的序列.....…