题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5795 A Simple Nim Time Limit: 2000/1000 MS (Java/Others)Memory Limit: 65536/65536 K (Java/Others) 问题描述 Two players take turns picking candies from n heaps,the player who picks the last one will win the…

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SG打表找规律 HDU 5795 题目连接 #include<iostream> #include<cstdio> #include<cmath> #include<algorithm> #include<cstring> using namespace std; #define MAXN 10000 int sg[MAXN],visit[MAXN]; int getsg(int n) { int i,j; ) return sg[n]; mem…

S-Nim HDU 1536 博弈 sg函数 题意 首先输入K,表示一个集合的大小,之后输入集合,表示对于这对石子只能去这个集合中的元素的个数,之后输入 一个m表示接下来对于这个集合要进行m次询问,之后m行,每行输入一个n表示有n个堆,每堆有n1个石子,问这一行所表示的状态是赢还是输,如果赢输入W否则L. 解题思路 如果没有每次取石子个数的限制的话,那么仅仅需要把每堆石子的个数进行异或运算即可,如果结果不是1,那么先手赢,反之后手赢. 但是这里对每次取石子的个数进行了限制,每次只能从几个数中进行…

A Simple Nim 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5795 Description Two players take turns picking candies from n heaps,the player who picks the last one will win the game.On each turn they can pick any number of candies which come from the…

http://acm.hdu.edu.cn/showproblem.php?pid=5795 A Simple Nim Problem Description   Two players take turns picking candies from n heaps,the player who picks the last one will win the game.On each turn they can pick any number of candies which come from…

A Simple Nim Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 79    Accepted Submission(s): 48 Problem Description Two players take turns picking candies from n heaps,the player who picks the las…

A Simple Nim Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Problem Description Two players take turns picking candies from n heaps,the player who picks the last one will win the game.On each turn they can pick an…

题意:在nim游戏的规则上再增加了一条,即可以将任意一堆分为三堆都不为0的子堆也视为一次操作. 分析:打表找sg值的规律即可. 感想:又学会了一种新的方法,以后看到sg值找不出规律的,就打表即可~ 打表代码如下: #include <stdio.h> #include <algorithm> #include <string.h> #include <set> using namespace std; +]; int main() { sg[] = ; ;i…

http://acm.hdu.edu.cn/showproblem.php?pid=5996 博弈论待补. 这题变化了一下,因为注意到奇数层的东西(层数从1开始),对手可以模仿地动,那就相当于没动. 比如从第5层,我选择去了第4,他去第3,我去2,他去1,结果还是到我.所以只需要把偶数层的东西,拿出来, 就是n个石头的博弈了. 异或起来,判断是否等于0,就可以了.博弈论好差,寒假补. #include <cstdio> #include <cstdlib> #include <…