leetcode 36】的更多相关文章

LeetCode:36. Valid Sudoku,数独是否有效 : 题目: LeetCode:36. Valid Sudoku 描述: Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules. The Sudoku board could be partially filled, where empty cells are filled with the character '.'. A partiall…
目录 # 前端与算法 leetcode 36. 有效的数独 题目描述 概要 提示 解析 算法 传入[['5', '3', '.', '.', '7', '.', '.', '.', '.'],['6', '.', '.', '1', '9', '5', '.', '.', '.'],['.', '9', '8', '.', '.', '.', '.', '6', '.'],['8', '.', '.', '.', '6', '.', '.', '.', '3'],['4', '.', '.',…
leetcode 36 感觉就是遍历. 保存好状态,就是各行各列还有各分区divide的情况 用数组做. 空间小时间大 class Solution { public: bool isValidSudoku(vector<vector<char>>& board) { int row[9][9]={0},col[9][9]={0},div[9][9]={0}; int temp=0,dnum; for(int i=0;i<9;i++){ for(int j=0;j&l…
Determine if a 9x9 Sudoku board is valid. Only the filled cells need to be validated according to the following rules: Each row must contain the digits 1-9without repetition. Each column must contain the digits 1-9 without repetition. Each of the 9 3…
36. 有效的数独 判断一个 9x9 的数独是否有效.只需要根据以下规则,验证已经填入的数字是否有效即可. 数字 1-9 在每一行只能出现一次. 数字 1-9 在每一列只能出现一次. 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次. 上图是一个部分填充的有效的数独. 数独部分空格内已填入了数字,空白格用 '.' 表示. 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/valid-sudoku 著作权归领扣网络所有.商业转载请…
36. Valid Sudoku Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules. The Sudoku board could be partially filled, where empty cells are filled with the character '.'. A partially filled sudoku which is valid. Note:A valid Sudoku…
https://leetcode.com/problems/valid-sudoku/ Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules. The Sudoku board could be partially filled, where empty cells are filled with the character '.'. A partially filled sudoku which is…
题目链接: https://leetcode.com/problems/valid-sudoku/?tab=Description   给出一个二维数组,数组大小为数独的大小,即9*9  其中,未填入数字的数组值为’.’ 判断当前所给已知数组中所填的数字是否合法.     数独合法性判断: 1. 满足每一行的数字都只能是1~9,并且不能产生重复 2. 满足每一列的数字都只能是1~9,并且不能产生重复 3. 满足每一个3*3的正方形块中的数字只能是1~9,并且不能产生重复     判断过程: 初始…
没啥好说的,直接上就行 36. 有效的数独 class Solution { public boolean isValidSudoku(char[][] board) { Map<Character, Integer> map = new HashMap<>(); for (int i = 0; i < 9; i++) { map.clear(); for (int j = 0; j < 9; j++) { if (board[i][j] != '.') { if (m…
Problem: Determine if a Sudoku is valid, according to: Sudoku Puzzles - The Rules. The Sudoku board could be partially filled, where empty cells are filled with the character '.'. A partially filled sudoku which is valid. Note:A valid Sudoku board (p…