https://leetcode.com/problems/rising-temperature/description/ 题目需要选出今天比昨天气温高的ID 用join,默认是inner join需要左右两边同时有才行.然后就是用on判断,首先判断其是相邻的两天. 用sql的DateDiff函数判断. 不知道为何用的和网上的结论相反 DateDiff(b, a) = 1表示b是a的下一天,才能ac # Write your MySQL query statement below select…

题目标签: 题目给了我们一个 温度表格,让我们找到 所有温度比之前一天高的,返回id. 建立 Weather w1, Weather w2,找到当w1 的温度 大于 w2 的时候,而且 w1 的日期是在w2 的后一天,返回id. Java Solution: Runtime:  338 ms, faster than 66 % Memory Usage: N/A 完成日期:06/01/2019 关键点:利用TO_DAYS 来比较日期. # Write your MySQL query state…

Given a Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates. +---------+------------+------------------+ | Id(INT) | Date(DATE) | Temperature(INT) | +---------+------------+----…

Given a Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates. +---------+------------------+------------------+ | Id(INT) | RecordDate(DATE) | Temperature(INT) | +---------+-----…

Given a Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates. +---------+------------+------------------+ | Id(INT) | Date(DATE) | Temperature(INT) | +---------+------------+----…

Given a Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates. +---------+------------+------------------+ | Id(INT) | Date(DATE) | Temperature(INT) | +---------+------------+----…

Given a Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates. +---------+------------+------------------+ | Id(INT) | Date(DATE) | Temperature(INT) | +---------+------------+----…

SQL架构 Create table If Not Exists Weather (Id int, RecordDate date, Temperature int) Truncate table Weather insert into Weather (Id, RecordDate, Temperature) values (') insert into Weather (Id, RecordDate, Temperature) values (') insert into Weather (…

Question: Given a Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates. +---------+------------+------------------+ | Id(INT) | Date(DATE) | Temperature(INT) | +---------+-------…

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…