problem 482. License Key Formatting solution1: 倒着处理,注意第一个字符为分隔符的情况要进行删除,注意字符的顺序是否正序. class Solution { public: string licenseKeyFormatting(string S, int K) { ) return NULL; ; string ans = ""; ; i>=; i--)//倒着处理. { char c = S[i]; if(S[i]=='-') c…

Question 482. License Key Formatting Solution 思路:字符串转化为char数组,从后遍历,如果是大写字母就转化为小写字母,如果是-就忽略,如果遍历了k个字符(排除-)就追加一个-. Java实现1:insert版(StringBuilder的append()与insert()效率比较) public String licenseKeyFormatting(String S, int K) { StringBuilder sb = new StringB…

You are given a license key represented as a string S which consists only alphanumeric character and dashes. The string is separated into N+1 groups by N dashes. Given a number K, we would want to reformat the strings such that each group contains ex…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/license-key-formatting/description/ 题目描述 You are given a license key represented as a string S which consists only alphanumeric character…

static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { public: string licenseKeyFormatting(string S, int K) { int len=S.length(); ; string res; ;i>=;i--) { char c=toupper(S[i]); if(c=='-') continue; res.push_b…

详见:https://leetcode.com/problems/license-key-formatting/description/ C++: class Solution { public: string licenseKeyFormatting(string S, int K) { string res = ""; int cnt = 0, n = S.size(); for (int i = n - 1; i >= 0; --i) { char c = S[i]; if…

482. License Key Formatting Easy You are given a license key represented as a string S which consists only alphanumeric character and dashes. The string is separated into N+1 groups by N dashes. Given a number K, we would want to reformat the strings…

Now you are given a string S, which represents a software license key which we would like to format. The string S is composed of alphanumerical characters and dashes. The dashes split the alphanumerical characters within the string into groups. (i.e.…

You are given a license key represented as a string S which consists only alphanumeric character and dashes. The string is separated into N+1 groups by N dashes. Given a number K, we would want to reformat the strings such that each group contains ex…

这是悦乐书的第241次更新,第254篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第108题(顺位题号是482).您将获得一个表示为字符串S的许可证密钥,该字符串仅包含字母数字字符和短划线.该字符串被N个破折号分成N + 1个组. 给定数字K,我们希望重新格式化字符串,使得每个组包含正好的K个字符,但第一个组可能比K短,但仍然必须包含至少一个字符.此外,必须在两个组之间插入短划线,并且所有小写字母都应转换为大写.给定非空字符串S和数字K,根据上述规则格式化字符串.例…