Because converting Foo** → const Foo** would be invalid and dangerous. C++ allows the (safe) conversion Foo* → Foo const*, but gives an error if you try to implicitly convert Foo** → const Foo**. The rationale for why that error is a good thing is gi…
static boolean foo(char c) { System.out.println(c); return true; } public static void main(String[] args) { int i = 0; for (foo('a'); foo('b') && (i < 2); foo('c')) { i++; foo('d'); } } 代码执行结果:a b d c b d c b 做这道面试题之前我们要了解for语句 1.各部分执行的顺序 2.各部分…
var Foo={} Foo.method = function() { var i = 0; return { a:function(){ console.log('aa', i++); }, b:function(){ console.log('bb', i++); } } } Foo.method().a(); Foo.method().b(); var bar=(function(){ var instance; function init(){ var i =0; return { a…