leetcode修炼之路——383. Ransom Note】的更多相关文章

题目是这样的 Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 all 
the 
magazines,
 write 
a 
function 
that 
will 
return 
true 
if 
the 
ransom 
 note 
can 
be 
constructed 
from 
the 
magazines ; 
otherwise, 
i…
383. Ransom Note[easy] Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return fal…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 [LeetCode] 题目地址:https://leetcode.com/problems/ransom-note/ Difficulty: Easy 题目描述 Given an arbitrary ransom note string and another string containing letters…

Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 all 
the 
magazines,
 write 
a 
function 
that 
will 
return 
true 
if 
the 
ransom 
 note 
can 
be 
constructed 
from 
the 
magazines ; 
otherwise, 
it 
wil…
Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false. Each letter in the…
Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false. Each letter in the…
题目描述: Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 all 
the 
magazines,
 write 
a 
function 
that 
will 
return 
true 
if 
the 
ransom 
 note 
can 
be 
constructed 
from 
the 
magazines ; 
otherwise, 
it…
题目: Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false. Each letter in…

Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 all 
the 
magazines,
 write 
a 
function 
that 
will 
return 
true 
if 
the 
ransom 
 note 
can 
be 
constructed 
from 
the 
magazines ; 
otherwise, 
it 
wil…
[抄题]: Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false. Each letter i…
-------------------------------------------- 思路就是进行频率统计. 统计一下第二个字符串字符出现次数++统计一下第一个字符串中字符出现次数--如果出现负数说明第二个中的字符不够用的. AC代码如下: public class Solution { public boolean canConstruct(String ransomNote, String magazine) { int book[]=new int[26]; for(int i=0;i…
最近公司搬家了,有两天没写了,今天闲下来了,继续开始算法之路. leetcode的题目如下: Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1. Examples: s = "leetcode" return 0. s = "loveleetcode", return 2. Note: Y…
给定一个赎金信 (ransom) 字符串和一个杂志(magazine)字符串,判断第一个字符串ransom能不能由第二个字符串magazines里面的字符构成.如果可以构成,返回 true :否则返回 false.(题目说明:为了不暴露赎金信字迹,要从杂志上搜索各个需要的字母,组成单词来表达意思.)注意:你可以假设两个字符串均只含有小写字母.canConstruct("a", "b") -> falsecanConstruct("aa",…
题目如下: Given two arrays, write a function to compute their intersection. Example: Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2]. Note: Each element in the result should appear as many times as it shows in both arrays. The result can be in…
哈哈,我又来了.昨天发现题目太简单就没有放上来,今天来了一道有序链表的题.题目如下: Given a sorted linked list, delete all duplicates such that each element appear only once. For example, Given 1->1->2, return 1->2. Given 1->1->2->3->3, return 1->2->3. 题目分析:简单来说就是去除有序链…
题目: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 题目分析: 将罗马数字转换成阿拉伯数字,规则如下:罗马数字共有七个,即I(1),V(5),X(10),L(50),C(100),D(500),M(1000). 按照下面的规则可以表示任意正整数. 重复数次:一个罗马数字重复几次,就表示这个数的几倍.右加左减:在一个较大的罗马数…
383. Ransom Note Easy Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return fals…

Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 all 
the 
magazines,
 write 
a 
function 
that 
will 
return 
true 
if 
the 
ransom 
 note 
can 
be 
constructed 
from 
the 
magazines ; 
otherwise, 
it 
wil…
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3937 访问. 给定一个赎金信 (ransom) 字符串和一个杂志(magazine)字符串,判断第一个字符串ransom能不能由第二个字符串magazines里面的字符构成.如果可以构成,返回 true :否则返回 false. (题目说明:为了不暴露赎金信字迹,要从杂志上搜索各个需要的字母,组成单词来表达意思.) 注意:你可以假设两个字符串均只含有小写字母.…
题目:Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false. Each letter in t…
Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false. Each letter in the…
题目描述: 
Given
 an 
arbitrary
 ransom
 note
 string 
and 
another 
string 
containing 
letters from
 all 
the 
magazines,
 write 
a 
function 
that 
will 
return 
true 
if 
the 
ransom 
 note 
can 
be 
constructed 
from 
the 
magazines ; 
otherwise, 
i…
Java工程师修炼之路(校招总结) 前言 在下本是跨专业渣考研的985渣硕一枚,经历研究生两年的学习积累,有幸于2019秋季招聘中拿到几个公司的研发岗offer,包括百度,阿里,腾讯,今日头条,网易,华为等. 一路走来也遇到很多困难,也踩了很多坑,同时我自己也探索了很多的学习方法,总结了很多心得体会,并且,我对校园招聘也做了一些研究和相应的准备. 在今年的秋季招聘结束以后,我也决定把这些东西全部都写成文字,做成专题,以便分享给更多未来将要参加校招的同学. 微信公众号[程序员江湖] 作者黄小斜,斜…
Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false. Each letter in the…
今天起,我会不定期更新我的java修炼之路, 2017.7.10,星期一 我参见了河南青云的培训班,这一天是我们的开班典礼. 我会不定期的总结我的学习笔记,大家喜欢的可以看看,不喜勿喷. 写代码: 1,明确需求.我要做什么? 2,分析思路.我要怎么做?1,2,3 3,确定步骤.每一个思路部分用到那些语句,方法,和对象. 4,代码实现.用具体的java语言代码把思路体现出来.   学习新技术的四点: 1,该技术是什么? 2,该技术有什么特点(使用注意) 3,该技术怎么使用.demo 4,该技术什么…
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这是悦乐书的第212次更新,第225篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第80题(顺位题号是383).给定一个任意赎金票据字符串和另一个包含所有杂志字母的字符串,如果赎金票据可以从杂志中构建,则写一个函数将返回true;否则,它将返回false.杂志字符串中的每个字母只能在赎金票据中使用一次.例如: canConstruct("a","b") - > false canConstruct("aa",&…
#-*- coding: UTF-8 -*- class Solution(object):       def canConstruct(self, ransomNote, magazine):        ransomNote=list(ransomNote)        magezine=list(magazine)                for ransom in ransomNote:            if(magezine.__contains__(ransom))…