Add Strings Leetcode】的更多相关文章

Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…
这些题目是高精度加法和高精度乘法相关的,复习了一下就做了,没想到难住自己的是C++里面string的用法. 原题地址: 415 Add Strings:https://leetcode.com/problems/add-strings/description/ 67 Add Binary: https://leetcode.com/problems/add-binary/description/ 43 Multiply Strings:https://leetcode.com/problems/…
LeetCode--Add Strings Question Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 doe…
415. Add Strings Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain…
problem 415. Add Strings solution: class Solution { public: string addStrings(string num1, string num2) { ; ; ; string res = ""; || j>= || carry) { )?:(num1[i--]-)?:(num2[j--]-')) + carry;//注意运算符的优先级顺序. carry = tmp/; res = to_string(tmp%) + r…
415. Add Strings Easy Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not con…
原文题目: 447. Add Strings 解题: 字符串的当做整数来做加法,其实就是大数加法的简化版本 思路: 1)考虑不同位数,如"1234"+“45”,需要先处理低两位,再处理num1的高两位 2)考虑进位,相加大于10时就要进位,进位值 = sum/10: 3)考虑最高位的进位,如“5099”+“4987”最后得到了五位的“10086” AC代码: class Solution { public: string addStrings(string num1, string n…
Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…
原题链接在这里:https://leetcode.com/problems/add-strings/ 题目: Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9.…
Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 [LeetCode] 题目地址:https://leetcode.com/problems/add-strings/ Difficulty: Easy 题目描述 Given two non-negative integers num1 and num2 represented as string, return the sum of num1…
这是悦乐书的第223次更新,第236篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第90题(顺位题号是415).给定两个非负整数num1和num2表示为字符串,返回num1和num2的总和. 注意: num1和num2的长度均<5100. num1和num2都只包含数字0-9. num1和num2都不包含任何前导零. 您不能使用任何内置BigInteger库或直接将输入转换为整数. 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 6…
Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…
Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…
Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…
1.题目描述 2.问题分析 直接按照加法运算规则运算即可,注意进位问题. 3.代码 string addStrings(string num1, string num2) { if( num1.empty() ) return num2; if( num2.empty() ) return num1; string::reverse_iterator it1 = num1.rbegin() ; string::reverse_iterator it2 = num2.rbegin() ; stri…
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3873 访问. 给定两个字符串形式的非负整数 num1 和num2 ,计算它们的和. 注意: num1 和num2 的长度都小于 5100. num1 和num2 都只包含数字 0-9. num1 和num2 都不包含任何前导零. 你不能使用任何內建 BigInteger 库, 也不能直接将输入的字符串转换为整数形式. Given two non-negative…
Problem Description http://oj.leetcode.com/problems/multiply-strings/ Basic idea is to multiply two nums like we do caculation on paper, one by one digital multiplication, then add the temporary results together to get the final one. Be careful about…
Given two strings s and t, determine if they are isomorphic. Two strings are isomorphic if the characters in s can be replaced to get t. All occurrences of a character must be replaced with another character while preserving the order of characters.…
题目: Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100". 题解: 二进制加法都是从最低位(从右加到左).所以对两个字符串要从最后一位开始加,如果遇见长度不一的情况,就把短的字符串高位补0. 每轮计算要加上进位,最后跳出循环后要坚持进位是否为1,以便更新结果. 代码如下(from…
Question 893. Groups of Special-Equivalent Strings Solution 题目大意: AB两个字符串相等的条件是:A中偶数位出现的字符与B中偶数位出现的字符相同且奇数位出现的字符也相同 按上述判定相等字符串的规则求去重后字符串的个数 思路: strHash函数,传一个字符串,返回该字符串的奇数位字符和偶数位字符出现的在字母表中的分布 构造一个set来存储每个字符串的strHash后的结果 Java实现: public int numSpecialEq…
Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 算法:模拟加法过程 class Solution { public: string addBinary(string a, string b) { int len1=a.size(); int len2=b.size(); ; rev…
Given a string of numbers and operators, return all possible results from computing all the different possible ways to group numbers and operators. The valid operators are +,- and *. Example 1 Input: "2-1-1". ((2-1)-1) = 0 (2-(1-1)) = 2 Output: …
Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…
题目: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题解: 题意就是给你两个字符串型的数字,给这两个数字做乘法. 如果直接转换成Integer做乘法就会溢出. 所以要一步一步来. 下面讲解引用自(http://leetcodeno…
[抄题]: 以字符串的形式给出两个非负整数 num1 和 num2,返回 num1和 num2 的和. 比如一个50位+一个100位. 给定 num1 = "123",num2 = "45" 返回 "168" [暴力解法]: 时间分析: 空间分析: [思维问题]: [一句话思路]: [输入量]:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): [画图]: [一刷]: sum求和或者循环退出的条件都是i j &g…
Design an algorithm to encode a list of strings to a string. The encoded string is then sent over the network and is decoded back to the original list of strings. Machine 1 (sender) has the function: string encode(vector<string> strs) { // ... your…
Given a string, we can "shift" each of its letter to its successive letter, for example: "abc" -> "bcd". We can keep "shifting" which forms the sequence: "abc" -> "bcd" -> ... -> &quo…
给定两个字符串形式的非负整数 num1 和num2 ,计算它们的和.注意:    num1 和num2 的长度都小于 5100.    num1 和num2 都只包含数字 0-9.    num1 和num2 都不包含任何前导零.    你不能使用任何內建 BigInteger 库, 也不能直接将输入的字符串转换为整数形式.详见:https://leetcode.com/problems/add-strings/description/C++: class Solution { public:…
Question 859. Buddy Strings Solution 题目大意: 两个字符串,其中一个字符串任意两个字符互换后与另一个字符串相等,只能互换一次 思路: diff 记录不同字符数 两个字符串长度不同 return false 两个字符串长度相同: abc abd 无重复,diff == 1 ca[3] != cb[3] return false abc abc 无重复,diff == 0 return false ab ba 无重复,diff == 2 return true…