hdu 1316 How Many Fibs? (模拟高精度)】的更多相关文章

题目大意: 问[s,e]之间有多少个 斐波那契数. 思路分析: 直接模拟高精度字符串的加法和大小的比較. 注意wa点再 s 能够从 0 開始 那么要在推断输入结束的时候注意一下. #include <cstdio> #include <iostream> #include <cstring> #include <algorithm> using namespace std; struct node { char str[111]; int len; void…
题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1316 How Many Fibs? Description Recall the definition of the Fibonacci numbers: $f_1 := 1$ $f_2 := 2$ $f_n := f_{n-1} + f_{n-2} \ \ (3 \leq n)$ Given two numbers a and b, calculate how many Fibonacci num…
//  大数继续 Problem Description Recall the definition of the Fibonacci numbers:  f1 := 1  f2 := 2  fn := fn-1 + fn-2 (n >= 3)  Given two numbers a and b, calculate how many Fibonacci numbers are in the range [a, b].    Input The input contains several t…
题目 /** * compareTo:根据该数值是小于.等于.或大于 val 返回 -1.0 或 1: public int compareTo(BigInteger val) 将此 BigInteger 与指定的 BigInteger 进行比较. 对于针对六个布尔比较运算符 (<, ==, >, >=, !=, <=) 中的每一个运算符的各个方法,优先提供此方法. 执行这些比较的建议语句是:(x.compareTo(y) <op> 0), 其中 <op>…
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题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4814 题目大意: 把一个正整数表示为φ进制, φ = (1+√5)/2 . 且已知: 1. φ + 1 = φ 2 ,所以有11(φ) = 100(φ),且要求11要转变为100 2. 2 * φ 2  = φ3 + 1 . 解题思路: 观察发现,2 = 10.01.所以对于一个数N,能够从N/2 推导得到,是一个模拟的过程.我比赛的时候居然用了高速幂... 代码: #include<cstdio>…