Zipper Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 59   Accepted Submission(s) : 26 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Given three strings, you are t…

Zipper Problem Description Given three strings, you are to determine whether the third string can be formed by combining the characters in the first two strings. The first two strings can be mixed arbitrarily, but each must stay in its original order…

目录 题目地址 题干 代码和解释 参考 题目地址 hdu1501 题干 代码和解释 最优子结构分析:设这三个字符串分别为a.b.c,如果a.b可以组成c,那么c的最后一个字母必定来自a或者b的最后一个字母.c去除最后一位,就变成由a-1和b或者a和b-1构成c-1的问题. 状态转移方程:DP[i][j]表示c中i个字符来自于a,j个字符来自于b,即由a的前i个字符和b的前j个字符组成c的前i+j个字符.DP[i][j]为1则真,为0则假. /*给3个字符串,让你判断能不能组合前两个字符串来获得第…

题目链接:http://poj.org/problem?id=2192 http://acm.split.hdu.edu.cn/showproblem.php?pid=5707 http://acm.split.hdu.edu.cn/showproblem.php?pid=1501 这三道题除了输入输出格式不一样,其他都一样,意思是给你三个字符串,问你能不能由前两个组成第三个,要按顺序: 但是hdu5707和poj2192数据太水,直接判断字符个数,然后一个一个的判断先后顺序是否满足即可,但是这…

http://poj.org/problem?id=2192 Zipper Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 17585   Accepted: 6253 Description Given three strings, you are to determine whether the third string can be formed by combining the characters in the…

  Zipper Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 8072    Accepted Submission(s): 2843 Problem Description Given three strings, you are to determine whether the third string can be formed…

Zipper Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 4884    Accepted Submission(s): 1742 Problem Description Given three strings, you are to determine whether the third string can be formed…

意甲冠军  是否可以由串来推断a,b字符不改变其相对为了获取字符串的组合c 本题有两种解法  DP或者DFS 考虑DP  令d[i][j]表示是否能有a的前i个字符和b的前j个字符组合得到c的前i+j个字符  值为0或者1  那么有d[i][j]=(d[i-1][j]&&a[i]==c[i+j])||(d[i][j-1]&&b[i]==c[i+j])   a,b的下标都是从1開始的  注意0的初始化 #include<cstdio> #include<cs…

Zipper Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 15277   Accepted: 5393 Description Given three strings, you are to determine whether the third string can be formed by combining the characters in the first two strings. The first tw…

ListZipper 模块 $ cabal install ListZipper Installed ListZipper-1.2.0.2 Prelude> :m +Data.List.Zipper Prelude Data.List.Zipper> Zipper 和 ListZipper Zipper 是一种带焦点(focus,也称游标, cursor)的数据结构.使用 Zipper 可以很方便的在底层数据结构中进行遍历,更新,插入,删除等操作. ListZipper 是建立在 List 这…