思路: 其实求解很简单直接说解法,移动K个后 上下的角动量最小,能肯定是相连的(n-k)个,至于为什么 你自己好好想想(easy): 对于一些等质量的质点中心在 所在位置和除以点的个数 average=sum[l,l+(n-k)-1]/(n-k); 一个点的值: (pi-average)* (pi-average)  也就是 pi^2+avery^2 - 2*pi*average  多个点相加也就是 ∑pi^2+(n-k)*sum*sum/(n-k)/(n-k)   -  2*∑pi*sum/(…

HDU 5073 Galaxy (2014 Anshan D简单数学) 题目链接http://acm.hdu.edu.cn/showproblem.php?pid=5073 Description Good news for us: to release the financial pressure, the government started selling galaxies and we can buy them from now on! The first one who bought…

主题链接:http://acm.hdu.edu.cn/showproblem.php? pid=5073 Galaxy Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 768    Accepted Submission(s): 179 Special Judge Problem Description Good news for…

主题链接:http://acm.hdu.edu.cn/showproblem.php? pid=5073 Galaxy Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 768    Accepted Submission(s): 179 Special Judge Problem Description Good news for…

Galaxy Problem's Link:   http://acm.hdu.edu.cn/showproblem.php?pid=5073 Mean: 在一条数轴上,有n颗卫星,现在你可以改变k颗卫星的位置,使得剩下的n-k颗卫星到某个点(不固定)的距离的平方和最小. 抽象成数学语言后等价于:数轴上有n个点,现在去掉k个点,使得剩下的n-k个点的方差最小,求方差*n的值. analyse: 一道让人很容易想偏的数学题.首先说一下我的思路: 1)我们最终的目的是让这n-k个点尽量的集中,所以去…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5073 解题报告:在一条直线上有n颗星星,一开始这n颗星星绕着重心转,现在我们可以把其中的任意k颗星星移动到这条直线上的任意位置然后围绕这个新的重心转,   这个星系的惯性值I = w1 * d1^2 + w2 * d2 ^ 2 +......+wn * dn ^ 2,其中wi表示第i颗星星的重量,di表示第i颗星星到这个星系的重心的距离.然后现在要你求转移k颗星星之后惯性值最小是多少? n颗星星转移…

Description Good news for us: to release the financial pressure, the government started selling galaxies and we can buy them from now on! The first one who bought a galaxy was Tianming Yun and he gave it to Xin Cheng as a present. To be fashionable,…

Galaxy                                                                   Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others)                                                                                  Total Subm…

Galaxy Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 262144/262144 K (Java/Others) Total Submission(s): 556    Accepted Submission(s): 127 Special Judge Problem Description Good news for us: to release the financial pressure, the government…

0.5 题意:有n(n<=5e4)个质点位于一维直线上,现在你可以任意移动其中k个质点,且移动到任意位置,设移动后的中心为e,求最小的I=(x[1]-e)^2+(x[2]-e)^2+(x[3]-e)^2.....(x[n]-e)^2; #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <cmath> #include &l…