解题报告 之 HDU5305 Friends Description There are  people and  pairs of friends. For every pair of friends, they can choose to become online friends (communicating using online applications) or offline friends (mostly using face-to-face communication). Ho…

Friends Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 163    Accepted Submission(s): 61 Problem Description There are n people and m pairs of friends. For every pair of friends, they can choo…

Friends Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 2329    Accepted Submission(s): 1150 Problem Description There are n people and m pairs of friends. For every pair of friends, they can c…

Friends Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2945    Accepted Submission(s): 1413 Problem Description There are n people and m pairs of friends. For every pair of friends, they can ch…

把这题想复杂了,一直在考虑怎么快速的判断将选的边和已选的边无冲突,后来经人提醒发现这根本没必要,反正数据也不大开两个数组爆搜就OK了,搜索之前要先排除两种没必要搜的情况,这很容易想到,爆搜的时候注意几个小细节就可以了(代码代码注释中已标好) #include<cstdio> #include<cstring> #include<iostream> #include<vector> #include<utility> using namespace…

Friends Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 668    Accepted Submission(s): 313 Problem Description There are n people and m pairs of friends. For every pair of friends, they can cho…

题目:pid=5305">http://acm.hdu.edu.cn/showproblem.php?pid=5305 题意:给定N个人和M条朋友关系,是朋友关系的两个人之间有两种联系方式online和offline.使每一个人的online的数量和offline的数量相等,求方案数. 分析:因为M<=28,暴力枚举的话2^28非常大,会超时.能够考虑把全部的状态平分成两半,即枚举前面M/2条关系,暴力求出前面的2^(M/2)种状态,然后枚举后面M/2条关系,暴力求出后面2^(M/2…

Problem Description There are n people and m pairs of friends. For every pair of friends, they can choose to become online friends (communicating using online applications) or offline friends (mostly using face-to-face communication). However, everyo…