【LeetCode 127. Word Ladder 单词接龙(C++/Java)】的更多相关文章

LeetCode 127. Word Ladder 单词接龙(C++/Java)

题目: Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word must exist in the wor…

[leetcode]127. Word Ladder单词接龙

Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word must exist in the word li…

[LeetCode] 127. Word Ladder 单词阶梯

Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word must exist in the word li…

127 Word Ladder 单词接龙

给出两个单词(beginWord 和 endWord)和一个字典,找到从 beginWord 到 endWord 的最短转换序列,转换需遵循如下规则:    每次只能改变一个字母.    变换过程中的中间单词必须在字典中出现.例如,给出:beginWord = "hit"endWord = "cog"wordList = ["hot","dot","dog","lot","lo…

leetcode 127. Word Ladder、126. Word Ladder II

127. Word Ladder 这道题使用bfs来解决,每次将满足要求的变换单词加入队列中. wordSet用来记录当前词典中的单词,做一个单词变换生成一个新单词,都需要判断这个单词是否在词典中,不在词典中就不能加入队列. pathCnt用来记录遍历到的某一个词使用的次数,做一个单词变换生成一个新单词,都需要判断这个单词是否在pathCnt中,如果在,则说明之前已经达到过,这次不用再计算了,因为这次计算的path肯定比之前多.pathCnt相当于剪枝. class Solution { pub…

Leetcode#127 Word Ladder

原题地址 BFS Word Ladder II的简化版(参见这篇文章) 由于只需要计算步数,所以简单许多. 代码: int ladderLength(string start, string end, unordered_set<string> &dict) { if (start == end) ; unordered_set<string> old; queue<string> layer; ; layer.push(start); while (!laye…

leetcode@ [127] Word Ladder (BFS / Graph)

https://leetcode.com/problems/word-ladder/ Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time Each…

leetcode 127. Word Ladder ----- java

Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time Each intermediate word must exist in the word li…

[LeetCode] 127. Word Ladder _Medium tag: BFS

Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time. Each transformed word must exist in the word li…

Java for LeetCode 127 Word Ladder

Given two words (beginWord and endWord), and a dictionary, find the length of shortest transformation sequence from beginWord to endWord, such that: Only one letter can be changed at a time Each intermediate word must exist in the dictionary For exam…