差分数列+字符串处理 题意:是让你判断一个整系数多项式的值是否一直都能被一个所给的正整数所整除. 通过对差分数列的不断求导,我们可以发现,对于任意多项式P,我们只需要判断n从1到k+1是否满足就行了,其中,k为多项式P中的最高次数. 可以先了解一下差分数列. #include <iostream> #include <cstdio> #include<cstdlib> #include<cctype> #include<string> #incl…

转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud Always an integer Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Combinatorics is a branch of mathematics chiefly concerned with counting discrete objects. For instanc…

题目很简单,就是求表达式(P/D)的结果是不是整数.其中P是一个整系数的多项式,D是一个正整数. 把1-k(最高次)+1都试一次就好了.结论可以总结归纳得到.(k取 0, 1, 2 .... 的情况推一次,可以推出结论). // Asimple #include <iostream> #include <algorithm> #include <cstdio> #include <cstdlib> #include <queue> #includ…

UVALive - 4108 SKYLINE Time Limit: 3000MS     64bit IO Format: %lld & %llu Submit Status uDebug Description   The skyline of Singapore as viewed from the Marina Promenade (shown on the left) is one of the iconic scenes of Singapore. Country X would a…

UVALive - 3942 Remember the Word A potentiometer, or potmeter for short, is an electronic device with a variable electric resistance. It has two terminals and some kind of control mechanism (often a dial, a wheel or a slide) with which the resistance…

UVALive - 3942 Remember the Word Neal is very curious about combinatorial problems, and now here comes a problem about words. Know- ing that Ray has a photographic memory and this may not trouble him, Neal gives it to Jiejie. Since Jiejie can’t remem…

int是java提供的8种原始数据类型之一.Java为每个原始类型提供了封装类,Integer是java为int提供的封装类.int的默认值为0,而Integer的默认值为null,即Integer可以区分出未赋值和值为0的区别,int则无法表达出未赋值的情况,例如,要想表达出没有参加考试和考试成绩为0的区别,则只能使用Integer.在JSP开发中,Integer的默认为null,所以用el表达式在文本框中显示时,值为空白字符串,而int默认的默认值为0,所以用el表达式在文本框中显示时,结果…

题目传送门 /* 题意:本来有n个雕塑,等间距的分布在圆周上,现在多了m个雕塑,问一共要移动多少距离: 思维题:认为一个雕塑不动,视为坐标0,其他点向最近的点移动,四舍五入判断,比例最后乘会10000即为距离: 详细解释:http://www.cnblogs.com/zywscq/p/4268556.html */ #include <cstdio> #include <iostream> #include <algorithm> #include <cmath&…

题目链接:https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=4156 题目拷贝难度大我就不复制了. 题目大意:维护一个字符串,要求支持插入.删除操作,还有输出第 i 次操作后的某个子串.强制在线. 思路1:使用可持久化treap可破,详细可见CLJ的<可持久化数据结构的研究>. 思路2:rope大法好,详见:http…

Permutation Graphs Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Practice UVALive 6508 #include<stdio.h> #include<string.h> ],a[],b[],c[],b1[]; long long num; void merg_sort(int a[],int l,int r) { int…