Message Decowding Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 999    Accepted Submission(s): 468 Problem Description The cows are thrilled because they've just learned about encrypting messa…

1.链接地址: http://poj.org/problem?id=2141 http://bailian.openjudge.cn/practice/2141/ 2.题目: Message Decowding Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11784   Accepted: 6562 Description The cows are thrilled because they've just learn…

Message Passing Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 1187    Accepted Submission(s): 423 Problem Description There are n people numbered from 1 to n. Each people have a unique mes…

题意: 给一棵树,每一个结点都有一个信息,每一个时刻,某一对相邻的结点之间可以传递信息,那么存在一个最少的时间,使得所有的节点都可以拥有所有的信息.但是,题目不是求最短时间,而是求最短时间的情况下,有多少种传递方式:某一时刻传递信息的双方不一样则认为是不同的传递方式.(表述的不是很清楚,自己看原题了) 容易的出,最短的时间内,当然是每个节点将自己的信息想外传出去一次,并且接受一次信息,也就是树边的2倍[2*(n-1)]. 然后可以证明,在最短时间内,所有的传递方式都有一个“信息转换点”——其他节…

参考了: http://www.cnblogs.com/zhsl/archive/2013/08/10/3250755.html http://blog.csdn.net/chaobaimingtian/article/details/9852761 题意:一个有n个节点的树,每个节点存有一份独一无二的信息,要求用最小的步数,把每个节点的信息共享给所有的节点.一个节点把自己所包含的所有信息传递给相邻的一个节点为一步. 题目不是求最小的步数,而是问最小的步数下,信息传递的方法有多少种. 分析: 最…

HDU 4655 Cut Pieces 假设n个数构成的总数都分成了n段,总数是n*a1*a2*...*an.但是答案显然不会那么多. 对于相邻的两个ai,ai+1,如果选择相同的颜色,那么就减少了a1*a2*...*ai-1*min(ai,ai+1)*ai+2*ai+3*...*an. 不妨假设n=3,三个数分别是a,b,c.且a<b<c. 对于所有的排列,只有a,c,b是最优的,结果是3*a*b*c-a*b-b. 当n>3的时候同样可以得到结论:a1,an,a2,an-1...使得总…

2992.357000 1000 A+B Problem1214.840000 1002 487-32791070.603000 1004 Financial Management880.192000 1003 Hangover792.762000 1001 Exponentiation752.486000 1006 Biorhythms705.902000 1005 I Think I Need a Houseboat686.540000 1011 Sticks647.566000 1007…

以下是poj百道水题,新手可以考虑从这里刷起 搜索1002 Fire Net1004 Anagrams by Stack1005 Jugs1008 Gnome Tetravex1091 Knight Moves1101 Gamblers1204 Additive equations 1221 Risk1230 Legendary Pokemon1249 Pushing Boxes 1364 Machine Schedule1368 BOAT1406 Jungle Roads1411 Annive…

一.   Spring DI 依赖注入 利用spring IOC实例化了对象,而DI将实例化的对象注入到需要对象的地方,完成初始化任务. 对象由spring创建,之后再由spring给属性赋值 spring提供两种方式设置属性值: ① setter方法注入 ②构造方法注入 二.   set方法注入 2.1单值注入 Cat有type和age属性,采用单值注入的方式,进行初始化. package com.hdu.setter; import java.io.Serializable; public…

---------------  VM Arguments---------------  jvm_args: -Dosgi.requiredJavaVersion=1.6 -Dhelp.lucene.tokenizer=standard -Xms40m -Xmx256m -XX:MaxPermSize=128m java_command: <unknown>java_class_path (initial): C:\e\eclipse4.2\\plugins/org.eclipse.equi…

题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=5558 Problem Description Alice wants to send a classified message to Bob. She tries to encrypt the message with her original encryption method. The message is a string S, which consists of Nlowercase let…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1509 Windows Message Queue Description Message queue is the basic fundamental of windows system. For each process, the system maintains a message queue. If something happens to this process, such as mous…

Clairewd’s message 题意:先一个转换表S,表示第i个拉丁字母转换为s[i],即a -> s[1];(a为明文,s[i]为密文).之后给你一串长度为n<= 100000的前面为密文后面为明文的串:让你通过密码转换表S在这个串的后面添加字符,使得前面的密文翻译成明文之后与后面相对应,最后输出添加字符后的串(前面密文照常输出): Sample Input 2 abcdefghijklmnopqrstuvwxyz abcdab qwertyuiopasdfghjklzxcvbnm q…

题目链接:hdu 3410 Passing the Message 题意: 说那么多,其实就是对于每个a[i],让你找他的从左边(右边)开始找a[j]<a[i]并且a[j]=max(a[j])(k+1<j<i),a[k]>a[i]. 题解: 从左往右维护一个递减的单调队列,每次都从尾巴开始把比a[i]的踢掉,最后踢的那个就是答案. 右边同理. #include<bits/stdc++.h> #define F(i,a,b) for(int i=a;i<=b;i++…

http://acm.hdu.edu.cn/showproblem.php?pid=4300 Clairewd’s message Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4411    Accepted Submission(s): 1676 Problem Description Clairewd is a member of…

Isabella's Message Time Limit: 20 Sec  Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=4119 Description Isabella and Steve are very good friends, and they often write letters to each other. They exchange funny experiences, talk ab…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4300 Problem Description Clairewd is a member of FBI. After several years concealing in BUPT, she intercepted some important messages and she was preparing for sending it to ykwd. They had agreed that ea…

后缀数组的买1送2题... HDU的那题数据实在是太水了,后来才发现在COJ和POJ上都是WA..原因在一点:在建立sa数组的时候里面的n应该是字符串长度+1....不懂可以去看罗大神的论文... 就是利用后缀数组模板求最长公共子串. #include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #include<string> #include<cmat…

Isabella's Message Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1365 Accepted Submission(s): 400 Problem Description Isabella and Steve are very good friends, and they often write letters to ea…

题目链接 Problem Description Message queue is the basic fundamental of windows system. For each process, the system maintains a message queue. If something happens to this process, such as mouse click, text change, the system will add a message to the qu…

Problem Description Clairewd is a member of FBI. After several years concealing in BUPT, she intercepted some important messages and she was preparing for sending it to ykwd. They had agreed that each letter of these messages would be transfered to a…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4300 题目大意:题目大意就是给以一段字符xxxxzzz前面x部分是密文z部分是明文,但是我们不知道是从哪里将密文和明文分开的, 密文是完整的,明文可能是不完整的,需要你补全,使得明文长度尽可能短. 解题思路: 因为密文至少占一半长度,所以从mid~len先假设为明文,然后将明文转成密文求出nxt[len](nxt[len]<=len-nxt[eln],不断递归nxt[len]直到满足条件)即为明文长…

Clairewd is a member of FBI. After several years concealing in BUPT, she intercepted some important messages and she was preparing for sending it to ykwd. They had agreed that each letter of these messages would be transfered to another one according…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1509 题目大意:每一次输入都有序号和优先级,优先级小的先输出,优先级相同的话则序号小的先输出!第一次用优先队列,暂时对优先队列的理解即:输出最小的~AC代码,供参考! #include <iostream> #include <cstdio> #include <queue> using namespace std; struct node { ]; int a,b,c;…

Passing the Message What a sunny day! Let’s go picnic and have barbecue! Today, all kids in “Sun Flower” kindergarten are prepared to have an excursion. Before kicking off, teacher Liu tells them to stand in a row. Teacher Liu has an important messag…

先上题目: Distribute Message Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1186    Accepted Submission(s): 547 Problem Description The contest’s message distribution is a big thing in prepare. Ass…

Windows Message QueueTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9202    Accepted Submission(s): 3836 Problem DescriptionMessage queue is the basic fundamental of windows system. For each pr…

The contest’s message distribution is a big thing in prepare. Assuming N students stand in a row, from the row-head start transmit message, each person can transmit message to behind M personals, and how many ways could row-tail get the message? Inpu…

Clairewd’s message Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 10376    Accepted Submission(s): 3709 Problem Description Clairewd is a member of FBI. After several years concealing in BUPT,…

HDU - 4300 题意:这个题目好难读懂,,先给你一个字母的转换表,然后给你一个字符串密文+明文,密文一定是全的,但明文不一定是全的,求最短的密文和解密后的明文: 题解:由于密文一定是全的,所以他的长度一定大于整个字符串的一半.将这一半先解密,然后和后缀对比一下,求最长的公共前缀.那么就转换为了拓展kmp问题. 1 #include<bits/stdc++.h> 2 using namespace std; 3 4 const int maxn=100010; //字符串长度最大值 5 i…