Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 分析: 罗马数字是由字符I,V,X,L,C,D,M等等表示的,其中 I = ; V = ; X = ; L = ; C = ; D = ; M = ; 接下来应该是V开始的重复,但是上面要加一个横线,表示对应数字的1000倍. 而且对于某位上(以个位为例), – ,应该是:I,II,…

Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 罗马数转化成数字问题,我们需要对于罗马数字很熟悉才能完成转换.以下截自百度百科: 罗马数字是最早的数字表示方式,比阿拉伯数字早2000多年,起源于罗马. 如今我们最常见的罗马数字就是钟表的表盘符号:Ⅰ,Ⅱ,Ⅲ,Ⅳ(IIII),Ⅴ,Ⅵ,Ⅶ,Ⅷ,Ⅸ,Ⅹ,Ⅺ,Ⅻ…… 对应阿拉伯数字(就是现…

Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 之前那篇文章写的是罗马数字转化成整数(http://www.cnblogs.com/grandyang/p/4120857.html), 这次变成了整数转化成罗马数字,基本算法还是一样.由于题目中限定了输入数字的范围(1 - 3999), 使得题目变得简单了不少. 基本字符 I V…

题目描述: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 解题思路: 首先我们要了解罗马数字怎么写的 个位数举例 I, 1 ]II, 2] III, 3] IV, 4 ]V, 5 ]VI, 6] VII, 7] VIII,8 ]IX, 9 ·十位数举例 X, 10] XI, 11 ]XII, 12] XIII, 13] XIV,…

Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. ------------------------ 题是比较简单,但是解法中用了static block. public class Solution { private static Map<Character, Integer> map; static { map = new H…

Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. Solution 1: class Solution { public: string intToRoman(int num) { // 关键 , , , , , , , , , , , , }; const string symbol[] = {"M", "CM…

Roman to Integer Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 首先学习一下罗马数字的规则: 羅馬數字共有7個,即I(1).V(5).X(10).L(50).C(100).D(500)和M(1000).按照下述的規則可以表示任意正整數.需要注意的是罗马数字中没有“0”,與進位制無關.一般認為羅馬數字只用來記數,而…

问题: Given a roman numeral, convert it to an integer.Input is guaranteed to be within the range from 1 to 3999. 官方难度: Easy 翻译: 将一个范围在1-3999的罗马字符,转化成整数形式. 罗马字符的规则见上一章No.012. 输入不考虑非罗马字符,或错误的罗马字符形式,如"IVI". 需要一个翻译,罗马字符-数字的映射关系的字典方法. 依次根据罗马字符累加,但是要考虑4…

Integer to Roman Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999.   罗马数字的组数规则,有几条须注意掌握:(1)基本数字Ⅰ.X .C 中的任何一个,自身连用构成数目,或者放在大数的右边连用构成数目,都不能超过三个:放在大数的左边只能用一个.(2)不能把基本数字 V .L .D 中的任何一个作为小数放在大数的左边采…

Roman to Integer Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 思路:首先要学一下罗马数字是怎么表示的,参见百度百科 其实看了上面罗马数字的介绍,可以建一个对应表 把数字和字母对应起来.遇到 I X C且后面字母的数字更大时 减去当前数字,否则加上. int romanToInt(string s) { ; ];…

Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. , , , , ,, , , , , , , }; string romans[]={"M", "CM", "D", "CD", "C", "XC", "L&quo…

Given an integer, convert it to a roman numeral. The number is guaranteed to be within the range from 1 to 3999. Have you met this question in a real interview?     Clarification What is Roman Numeral? https://en.wikipedia.org/wiki/Roman_numerals htt…

Given a roman numeral, convert it to an integer. The answer is guaranteed to be within the range from 1 to 3999. Have you met this question in a real interview? Yes Clarification What is Roman Numeral? https://en.wikipedia.org/wiki/Roman_numerals htt…

Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. roman numerals: https://en.wikipedia.org/wiki/Roman_numerals Solution 1: class Solution { public: inline int romanInt(const char c) { switch(c…

Roman chart: http://literacy.kent.edu/Minigrants/Cinci/romanchart.htm Integer to Roman Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 解析:只有数字为 9 和 4 时,取一个小数放在左边.(把数字为 9 和 4 时的罗马符号看作一个原子,避免取…

首先简单介绍一下罗马数字,一下摘自维基百科 罗马数字共有7个,即I(1).V(5).X(10).L(50).C(100).D(500)和M(1000).按照下述的规则可以表示任意正整数.需要注意的是罗马数字中没有“0”,与进位制无关.一般认为罗马数字只用来记数,而不作演算. 重复数次:一个罗马数字重复几次,就表示这个数的几倍. 右加左减: 在较大的罗马数字的右边记上较小的罗马数字,表示大数字加小数字. 在较大的罗马数字的左边记上较小的罗马数字,表示大数字减小数字. 左减的数字有限制,仅限于I.X…

题目: Given an integer, convert it to a roman numeral.Input is guaranteed to be within the range from 1 to 3999. 官方难度: Medium 翻译: 给定一个范围在1-3999内的整数,将其转化成罗马数字. 补充资料: 罗马数字规则: 需要用到的罗马数字共有7个,即I(1).V(5).X(10).L(50).C(100).D(500)和M(1000).罗马数字中没有0. 一个罗马数字最多重复…

[本文链接] http://www.cnblogs.com/hellogiser/p/roman-to-integer-and-integer-to-roman.html [题目] 给出一个罗马数字,转换为阿拉伯数字.本题只考虑3999以内的数. 罗马数字有如下符号: Ⅰ(1)Ⅴ(5)Ⅹ(10)L(50)C(100)D(500)M(1000) 计数规则: (1).若干相同数字连写表示的数是这些罗马数字的和,如III=3: (2).小数字在大数字前面表示的数是用大数字减去小数字,如IV＝4: (3…

Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 解题思路: 类似上题,方法多多,本题直接给出上题中字典匹配的代码: JAVA实现: static public int romanToInt(String s) { int num=0; String Roman[][] = { {"", "I", &q…

Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 本题思路比较简单,难度主要集中在罗马数字本身,直接贴代码. 思路一,从高位开始: JAVA: static public String intToRoman(int number) { int[] values = { 1000, 900, 500, 400, 100, 90, 50…

Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. Summary: When meeting C/X/I, remembers to search forward to check if there is a bigger number at the front. int romanToInt(string s) { ) ; ; ;…

Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 代码如下: public class Solution { public String intToRoman(int num) { int n=0; int[] nums={1000,500,100,50,10,5,1}; Map<Integer,String> map=new H…

Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. inline int c2n(char c) { switch(c) { ; ; ; ; ; ; ; ; } } class Solution { public: int romanToInt(string s) { // Start typing your C/C++ soluti…

Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. string intToRoman(int num) { string res; ]={'I','X','C','M'}; ]={'V','L','D'}; ,ld=,n=; ) { ld=num/n; num%=n; n/=; switch(ld) { :break; :{res+…

题目: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 思路:与12题正好相反,罗马数字基本字符集:I V X L C D M (1, 5, 10, 50, 100, 500, 1000).思路是从字符串最低位开始匹配,累加相应字符对应的阿拉伯数字,要注意的就是I,X,L(1,10,100)要判断是在左还是在右,在左就减在右就加.…

题目: Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 思路: 主要是了解罗马数和阿拉伯数字的对应关系,如下表: 由这个表基本上可以将1-3999范围的阿拉伯数字换成罗马数字.在处理阿拉伯数字时从高位开始匹配,将每个位的值找出对应罗马数字,串成字符串即可. public class Solution { public String…

13. Roman to Integer Total Accepted: 95998 Total Submissions: 234087 Difficulty: Easy Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 思路: 根据上一篇的关于罗马数字的解释,我们可以知道,在罗马数字中左减右加的原则,所以当较小的数在较大的数前面时…

12. Integer to Roman Total Accepted: 71315 Total Submissions: 176625 Difficulty: Medium Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 思路: 首先,我们得弄清楚罗马数字的计数方式.根据维基百科的介绍:https://zh.wikipedia.…

题目: Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999. 代码: class Solution { public: int romanToInt(string s) { ; std::map<char, int> symbol_value; char symbol_ori[size] = {'M','D','C','L','X',…

题目: Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 代码: class Solution { public: string intToRoman(int num) { ) return NULL; ; std::string symbol_ori[size] = {"M","D","C&…