Description It is 2084 and the year of Big Brother has finally arrived, albeit a century late. In order to exercise greater control over its citizens and thereby to counter a chronic breakdown in law and order, the Government decides on a radical mea…

/* ID Codes It is 2084 and the year of Big Brother has finally arrived, albeit a century late. In order to exercise greater control over its citizens and thereby to counter a chronic breakdown in law and order, the Government decides on a radical mea…

It is 2084 and the year of Big Brother has finally arrived, albeit a century late. In order to exercise greater control over its citizens and thereby to counter a chronic breakdown in law and order, the Government decides on a radical measure--all ci…

 ID Codes  Problem's Link:http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&category=3&problem=82&mosmsg=Submission+received+with+ID+14418598 Mean: 求出可重排列的下一个排列. analyse: 直接用STL来实现就可.自己手动写了一个,并不复杂.…

ID Codes Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 6281 Accepted: 3769 Description It is 2084 and the year of Big Brother has finally arrived, albeit a century late. In order to exercise greater control over its citizens and thereby…

C - ID Codes Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu Submit Status Appoint description:  System Crawler  (2014-05-12) Description  ID Codes  It is 2084 and the year of Big Brother has finally arrived, albeit a century l…

ID Codes Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 6229   Accepted: 3737 Description It is 2084 and the year of Big Brother has finally arrived, albeit a century late. In order to exercise greater control over its citizens and ther…

ID Codes Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 7644   Accepted: 4509 Description It is 2084 and the year of Big Brother has finally arrived, albeit a century late. In order to exercise greater control over its citizens and ther…

题意与解析 这题其实特别简单,求给定排列的后继.使用stl(next_permutation)可以方便地解决这个问题.但是,想要自己动手解就是另外一回事了.我的解法是从后往前找到第一个$a_i$比$a_j$小($i<j$)的,然后交换之,接下来i->end范围内重排序即可. 代码 /* *********************************************** Author :Sam X Created Time :2018年01月16日 星期二 08时44分26秒 Fil…

// 求下一个排列// 如果已经是最后一个排列// 就输出 No Successor// stl 或 自己写个 生成排列 我测试了下 两个速率是一样的.只是代码长度不同 /* #include <iostream> #include <string> #include<sstream> #include <cmath> #include <map> #include <stdio.h> #include <string.h>…