HDU1151:Air Raid(最小边覆盖)】的更多相关文章

题目链接:https://vjudge.net/problem/HDU-1151 Air Raid Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5630    Accepted Submission(s): 3785 Problem Description Consider a town where all the streets a…
Air Raid Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4591    Accepted Submission(s): 3072 Problem Description Consider a town where all the streets are one-way and each street leads from one…
Air Raid Problem Description Consider a town where all the streets are one-way and each street leads from one intersection to another. It is also known that starting from an intersection and walking through town's streets you can never reach the same…
题目: Air Raid Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 124 Accepted Submission(s): 102   Problem Description Consider a town where all the streets are one-way and each street leads from one…
Air Raid Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 7511   Accepted: 4471 Description Consider a town where all the streets are one-way and each street leads from one intersection to another. It is also known that starting from an i…
点击打开链接 有向无环图的最小路径覆盖 = 顶点数- 最大匹配 #include <queue> #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; const int maxn = 150; int g[maxn][maxn]; int n, m; int link[maxn]; bool used[…
题意 给定一个有向图,在这个图上的某些点上放伞兵,可以使伞兵可以走到图上所有的点.且每个点只被一个伞兵走一次.问至少放多少伞兵. 思路 裸的最小路径覆盖. °最小路径覆盖 [路径覆盖]在一个有向图G(V, E<u,v>)中,路径覆盖就是在图中找一些路经,使之覆盖了图中的所有顶点,且任何一个顶点有且只有一条路径与之关联(如果把这些路径中的每条路径从它的起始点走到它的终点,那么恰好可以经过图中的每个顶点一次且仅一次):如果不考虑图中存在回路,那么每条路径就是一个弱连通子集. [最小路径覆盖]最小路…
http://acm.hdu.edu.cn/showproblem.php?pid=1151 增广路的变种2:DAG图的最小路径覆盖=定点数-最大匹配数 #include<iostream> #include<stdio.h> #include<string.h> #include<stdlib.h> #include<math.h> using namespace std; ; int a[N][N]; int use[N]; int matc…
题意:     一个镇里所有的路都是单向路且不会组成回路. 派一些伞兵去那个镇里,要到达所有的路口,有一些或者没有伞兵可以不去那些路口,只要其他人能完成这个任务.每个在一个路口着陆了的伞兵可以沿着街去到其他路口.我们的任务是求出去执行任务的伞兵最少可以是多少个. 思路: 这个题就是个最小路径覆盖问题. 路径覆盖的定义是:在有向图中找一些路径,使之覆盖了图中的所有顶点,就是任意一个顶点都跟那些路径中的某一条相关联,且任何一个顶点有且只有一条路径与之关联,一个单独的顶点是一条路径.最小路径覆盖就是最…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1151 求最小路径覆盖 二分图最小路径覆盖=点的个数-最大匹配. 代码: #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> using namespace std; #define maxn 125 int g[maxn][maxn]; int vis[maxn]; in…