/* poj 2187 Beauty Contest 凸包:寻找每两点之间距离的最大值 这个最大值一定是在凸包的边缘上的! 求凸包的算法: Andrew算法! */ #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; struct Point{ Point(){} Point(int x, int y){ this->…

Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the world in order to spread goodwill bet…

http://poj.org/problem?id=2187 显然直径在凸包上(黑书上有证明).(然后这题让我发现我之前好几次凸包的排序都错了QAQ只排序了x轴.....没有排序y轴.. 然后本题数据水,暴力也能过... (之前一直以为距离是单增的,其实并不是,应该是三角形面积单增...) 考虑旋转卡壳 一篇好的文章:http://www.cnblogs.com/Booble/archive/2011/04/03/2004865.html 首先对踵点就是两条平行线夹紧凸包的两个点(或者3个点或4…

链接:http://poj.org/problem?id=2187 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the wor…

Beauty Contest 题意:给你一个数据范围在2~5e4范围内的横纵坐标在-1e4~1e4的点,问你任意两点之间的距离的最大值的平方等于多少? 一道卡壳凸包的模板题,也是第一次写计算几何的题,就看了些模板,关于预备知识;我是直接找到左下角的点,排好序之后,就直接形成凸包,之后调用rotating_calipers()求解:里面注意在凸包构造好之后,因为是++top的,所以在后面卡壳里面%top会出现问题,所以循环之后再一次++top;开始看graham()里面的while循环看了很久,其…

Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 25256   Accepted: 7756 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a…

转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 31214   Accepted: 9681 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty con…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 27276   Accepted: 8432 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bess…

id=2187">Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 27218   Accepted: 8410 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 27507   Accepted: 8493 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bess…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 36113   Accepted: 11204 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bes…

题面 Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the world in order to spread goodwill between farm…

题目链接:http://poj.org/problem?id=2187 Time Limit: 3000MS Memory Limit: 65536K Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of…

P1452 Beauty Contest 题意 求平面\(n(\le 50000)\)个点的最远点对 收获了一堆计算几何的卡点.. 凸包如果不保留共线的点,在加入上凸壳时搞一个相对栈顶,以免把\(n\)号点删走了 旋转卡壳和凸包都想一下更新的时候带不带等于号阿 Code: #include <cstdio> #include <algorithm> using std::max; const int N=5e4+10; int s[N],tot,n,p; struct Vector…

计算几何/旋转卡壳 学习旋转卡壳请戳这里~感觉讲的最好的就是这个了…… 其实就是找面积最大的三角形?...并且满足单调…… 嗯反正就是这样…… 这是一道模板题 好像必须写成循环访问?我在原数组后面复制了一遍点,结果挂了……改成cur=cur%n+1就过了QAQ //其实是不是数组没开够所以复制的方法就爆了? UPD:(2015年5月13日 20:40:45) 其实是我点保存在1~n里面,所以复制的时候不能写p[i+n-1]=p[i]; 而应该是p[i+n]=p[i];……QAQ我是傻逼 Sour…

Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 32708   Accepted: 10156 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a…

Luogu 1452 Beauty Contest 求平面最远点对,先求出凸包,再找凸包的直径. 使用旋转卡壳,直径一定出现在对踵点对间.比较不同点到同一直线距离可以用叉积算三角形面积来比较. 实现时注意关于栈的 \(top\) 的细节. #include<bits/stdc++.h> using namespace std; #define ll long long #define mp make_pair #define pii pair<int,int> inline int…

Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the world in order to spread goodwill bet…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 24283   Accepted: 7420 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bess…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 26180   Accepted: 8081 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bess…

Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the world in order to spread goodwill between farmers…

D - Beauty Contest Time Limit:3000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a r…

链接: http://poj.org/problem?id=2187 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=22013#problem/E Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 24254   Accepted: 7403 Description Bessie, Farmer John's prize cow, h…

 凸包(旋转卡壳) 大概理解了凸包A了两道模板题之后在去吃饭的路上想了想什么叫旋转卡壳呢?回来无聊就搜了一下,结果发现其范围真广. 凸包: 凸包就是给定平面图上的一些点集(二维图包),然后求点集组成的凸多边形,但是要包含所有的点. 求凸多边形的方法:Graham算法描述如下: Graham()算法先对点进行排序,有极角序和水平序两种排序方式.我们仍然以左下方的点作为基准点来通过叉积进行排序.利用STL里面的sort或者自己写个排序算法,排序所用时间为O(NlogN),极角序列如左图所示:极角排序…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 24431   Accepted: 7459 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bess…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 31414   Accepted: 9749 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bess…

原题如下: Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 42961   Accepted: 13307 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a resul…

Beauty Contest Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 38349   Accepted: 11851 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bes…

http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28417#problem/F 题目大意:给n个点,求相聚最远距离的平方(输出整形) 集体思路:先求出包围所有点的凸包,然后暴力枚举求解(直接暴力会超时) #include<iostream> #include<cmath> #include<string.h> #include<string> #include<stdio.h> #inc…

题目: http://poj.org/problem?id=1113 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=22013#problem/F Wall Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 26219   Accepted: 8738 Description Once upon a time there was a greedy King who…