E. Runaway to a Shadow 题目连接: http://www.codeforces.com/contest/681/problem/E Description Dima is living in a dormitory, as well as some cockroaches. At the moment 0 Dima saw a cockroach running on a table and decided to kill it. Dima needs exactly T…

D. Gifts by the List 题目连接: http://www.codeforces.com/contest/681/problem/D Description Sasha lives in a big happy family. At the Man's Day all the men of the family gather to celebrate it following their own traditions. There are n men in Sasha's fam…

C. Heap Operations 题目连接: http://www.codeforces.com/contest/681/problem/C Description Petya has recently learned data structure named "Binary heap". The heap he is now operating with allows the following operations: put the given number into the…

B. Economy Game 题目连接: http://www.codeforces.com/contest/681/problem/B Description Kolya is developing an economy simulator game. His most favourite part of the development process is in-game testing. Once he was entertained by the testing so much, th…

A. A Good Contest 题目连接: http://www.codeforces.com/contest/681/problem/A Description Codeforces user' handle color depends on his rating - it is red if his rating is greater or equal to 2400; it is orange if his rating is less than 2400 but greater or…

A. A Good Contest time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Codeforces user' handle color depends on his rating — it is red if his rating is greater or equal to 2400; it is orange if…

传说中做cf不补题等于没做 于是第一次补...这次的cf没有做出来DE D题的描述神奇 到现在也没有看懂 于是只补了E 每次div2都是hack前2~3题 终于打出一次hack后的三题了...希望以后能越来越好 早日..至少变成蓝色名字吧:) E题意 有一个蟑螂 人要打死它 给出蟑螂的坐标 速度 人的瞄准时间 再给出一些阴影(圆形且给出坐标与半径) 若蟑螂移动到阴影内会立即停下 人不能打到阴影中的蟑螂 问它不被打死的机率 蟑螂的移动方向是随机的 需要注意的是蟑螂只会朝一个方向走直线 所以我们对于…

C. Heap Operations time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Petya has recently learned data structure named "Binary heap". The heap he is now operating with allows the following…

C. Heap Operations time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Petya has recently learned data structure named "Binary heap". The heap he is now operating with allows the following…

B. Economy Game time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Kolya is developing an economy simulator game. His most favourite part of the development process is in-game testing. Once he…

用单调队列(从小到大),模拟一下就好了,主要是getMin比较麻烦,算了,都是模拟....也没什么好说的.. #include<cstdio> #include<map> #include<queue> #include<iostream> #include<stdlib.h> #include<string.h> #include<algorithm> using namespace std; priority_queu…

A. Peter and Snow Blower 题目连接: http://www.codeforces.com/contest/613/problem/A Description Peter got a new snow blower as a New Year present. Of course, Peter decided to try it immediately. After reading the instructions he realized that it does not…

Codeforces Round #366 (Div. 2) A I hate that I love that I hate it水题 #I hate that I love that I hate it n = int(raw_input()) s = "" a = ["I hate that ","I love that ", "I hate it","I love it"] for i in ran…

Codeforces Round #354 (Div. 2) Problems     # Name     A Nicholas and Permutation standard input/output 1 s, 256 MB    x3384 B Pyramid of Glasses standard input/output 1 s, 256 MB    x1462 C Vasya and String standard input/output 1 s, 256 MB    x1393…

直达–>Codeforces Round #368 (Div. 2) A Brain’s Photos 给你一个NxM的矩阵,一个字母代表一种颜色,如果有”C”,”M”,”Y”三种中任意一种就输出”#Color”,如果只有”G”,”B”,”W”就输出”#Black&White”. #include <cstdio> #include <cstring> using namespace std; const int maxn = 200; const int INF =…

 cf之路,1,Codeforces Round #345 (Div. 2) ps:昨天第一次参加cf比赛,比赛之前为了熟悉下cf比赛题目的难度.所以做了round#345连试试水的深浅.....       其实这个应该是昨天就写完的,不过没时间了,就留到了今天.. 地址:http://codeforces.com/contest/651/problem/A A. Joysticks time limit per test 1 second memory limit per test 256…

Codeforces Round #279 (Div. 2) 做得我都变绿了! Problems     # Name     A Team Olympiad standard input/output 1 s, 256 MB  x2377 B Queue standard input/output 2 s, 256 MB  x1250 C Hacking Cypher standard input/output 1 s, 256 MB  x740 D Chocolate standard in…

Codeforces Round #262 (Div. 2) 1003 C. Present time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Little beaver is a beginner programmer, so informatics is his favorite subject. Soon his info…

Codeforces Round #262 (Div. 2) 1004 D. Little Victor and Set time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Little Victor adores the sets theory. Let us remind you that a set is a group of…

A: 题目大意: 在一个multiset中要求支持3种操作: 1.增加一个数 2.删去一个数 3.给出一个01序列,问multiset中有多少这样的数,把它的十进制表示中的奇数改成1,偶数改成0后和给出的01序列相等(比较时如果长度不等各自用0补齐) 题解: 1.我的做法是用Trie数来存储,先将所有数用0补齐成长度为18位,然后就是Trie的操作了. 2.官方题解中更好的做法是,直接将每个数的十进制表示中的奇数改成1,偶数改成0,比如12345,然后把它看成二进制数10101,还原成十进制是2…

CF469 Codeforces Round #268 (Div. 2) http://codeforces.com/contest/469 开学了,时间少,水题就不写题解了,不水的题也不写这么详细了. A 水题 //#pragma comment(linker, "/STACK:102400000,102400000") #include<cstdio> #include<cmath> #include<iostream> #include<…

题目传送门 /* 贪心 + 模拟:首先,如果蜡烛的燃烧时间小于最少需要点燃的蜡烛数一定是-1(蜡烛是1秒点一支), num[g[i]]记录每个鬼访问时已点燃的蜡烛数,若不够,tmp为还需要的蜡烛数, 然后接下来的t秒需要的蜡烛都燃烧着,超过t秒,每减少一秒灭一支蜡烛,好!!! 详细解释:http://blog.csdn.net/kalilili/article/details/43412385 */ #include <cstdio> #include <algorithm> #i…

题目传送门 /* 题意:从前面找一个数字和末尾数字调换使得变成偶数且为最大 贪心:考虑两种情况:1. 有偶数且比末尾数字大(flag标记):2. 有偶数但都比末尾数字小(x位置标记) 仿照别人写的,再看自己的代码发现有清晰的思维是多重要 */ #include <cstdio> #include <iostream> #include <algorithm> #include <cmath> #include <cstring> #include…

#include <iostream> #include <string> using namespace std; int main(){ int n; cin >> n; string str; cin >> str; , x = ; ; i < n ; ++ i){ if(str[i] == 'B') cnt+=(x << i); } cout<<cnt<<endl; }   Codeforces Round…

Codeforces Round #160 (Div. 1) A - Maxim and Discounts 题意 给你n个折扣,m个物品,每个折扣都可以使用无限次,每次你使用第i个折扣的时候,你必须买q[i]个东西,然后他会送你{0,1,2}个物品,但是送的物品必须比你买的最便宜的物品还便宜,问你最少花多少钱,买完m个物品 题解 显然我选择q[i]最小的去买就好了 代码 #include<bits/stdc++.h> using namespace std; const int maxn =…

Codeforces Round #383 (Div. 2) A. Arpa's hard exam and Mehrdad's naive cheat 题意 求1378^n mod 10 题解 直接快速幂 代码 #include<bits/stdc++.h> using namespace std; long long quickpow(long long m,long long n,long long k) { long long b = 1; while (n > 0) { if…

Codeforces Round #271 (Div. 2) A - Keyboard 题意 给你一个字符串,问你这个字符串在键盘的位置往左边挪一位,或者往右边挪一位字符,这个字符串是什么样子 题解 模拟一下就好了 代码 #include<bits/stdc++.h> using namespace std; string s[3]; map<char,int>r,c; char ss[2][107]; int main() { s[0]="qwertyuiop"…

Codeforces Round #177 (Div. 1) A. Polo the Penguin and Strings 题意 让你构造一个长度为n的串,且里面恰好包含k个不同字符,让你构造的字符串字典序最小. 题解 先abababab,然后再把k个不同字符输出,那么这样就是最少 代码 #include<bits/stdc++.h> using namespace std; string s; int main() { int n,k; scanf("%d%d",&am…

Codeforces Round #182 (Div. 1)题解 A题:Yaroslav and Sequence1 题意: 给你\(2*n+1\)个元素,你每次可以进行无数种操作,每次操作必须选择其中n个元素改变符号,你的目的是使得最后所有数的和尽量大,问你答案是多少 题解: 感觉上就是构造题,手动玩一玩就知道,当n为奇数的时候,你可以通过三次操作,使得只会改变一个负数的符号.同理n为偶数的时候,每次要改变两个负数的符号. 所以答案如下: 当n为奇数的时候,答案为所有数的绝对值和 当n为偶数的…

题目大意 两个人轮流在一个字符串上删掉一个字符,没有字符可删的人输掉游戏 删字符的规则如下: 1. 每次从一个字符串中选取一个字符,它是一个长度至少为 3 的奇回文串的中心 2. 删掉该字符,同时,他选择的那个字符串分成了两个独立的字符串 现在问,先手是否必胜,如果先手必胜,输出第一步应该删掉第几个字符,有多解的话,输出序号最小的那个 字符串的长度不超过5000,只包含小写英文字母 做法分析 可以这样考虑:将所有的长度大于等于 3(其实只需要找长度为 3 的就行)的奇回文串的中心标记出来 我们将…