Maximum Depth of Binary Tree  Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 与Minimum Depth of Binary Tree对照看 解法一:递归,子树高度+1. /** * Defini…
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作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 方法一:BFS 方法二:DFS 参考资料 日期 题目地址:https://leetcode.com/problems/maximum-depth-of-binary-tree/ Total Accepted: 85334 Total Submissions: 188240 Difficulty: Easy 题目描述 Given a binary tr…
Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Solution: /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNo…
Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 很简单,直接上代码: /** * Definition for a binary tree node. * public class TreeNode { * int val; *…
题目: Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 代码:…
-------------------------------- 递归遍历即可 AC代码: /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public int maxDepth(TreeNode…
求树的最大深度 class Solution(object): def maxDepth(self, root): if not root: return 0 left = self.maxDepth(root.left) right = self.maxDepth(root.right) return left+1 if left>right else right+1 1 line python class Solution(object): def maxDepth(self, root):…
258. Add Digits Digit root 数根问题 /** * @param {number} num * @return {number} */ var addDigits = function(num) { var b = (num-1) % 9 + 1 ; return b; }; //之所以num要-1再+1;是因为特殊情况下:当num是9的倍数时,0+9的数字根和0的数字根不同. 性质说明 1.任何数加9的数字根还是它本身.(特殊情况num=0)        小学学加法的…
104. Maximum Depth of Binary Tree -- Easy 方法 使用递归 /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int…