题目: Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Input: intervals = [[1,3],[6,9]], newInter…

Insert Interval  Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9],…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Input: intervals = [[1,3],[6,9]], newInterval…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Input: intervals = [[1,3],[6,9]], newInterval…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […

Insert interval  题意简述:给定若干个数轴上的闭区间,保证互不重合且有序,要求插入一个新的区间,并返回新的区间集合,保证有序且互不重合. 只想到了一个线性的解法,所有区间端点,只要被其他区间覆盖,就是不合法的,把他们去掉后,就可以直接得到答案.设新区间为[left,right],那么,比left小的端点显然合法,比right大的端点显然也合法,left和right之间的端点显然不合法,然后判断Left和right是否合法即可.难度不大,代码有些细节需要注意. /** * Defi…

lc57 Insert Interval 仔细分析题目,发现我们只需要处理那些与插入interval重叠的interval即可,换句话说,那些end早于插入start以及start晚于插入end的interval都可以保留.我们只需要两个指针,i&j分别保存重叠interval中最早start和最晚end即可,然后将interval [i, j]插入即可 class Solution { public int[][] insert(int[][] intervals, int[] newInte…

Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9], insert and merge…

给出一个无重叠的按照区间起始端点排序的区间列表.在列表中插入一个新的区间,你要确保列表中的区间仍然有序且不重叠(如果有必要的话,可以合并区间).示例 1:给定区间 [1,3],[6,9],插入并合并 [2,5] 得到 [1,5],[6,9].示例 2:给定区间 [1,2],[3,5],[6,7],[8,10],[12,16],插入并合并 [4,9] 得到 [1,2],[3,10],[12,16].这是因为新的区间 [4,9] 与 [3,5],[6,7],[8,10] 重叠.详见:https://…

原题地址 遍历每个区间intervals[i]: 如果intervals[i]在newInterval的左边,且没有交集,把intervals[i]插入result 如果intervals[i]在newInterval的右边,且没有交集,如果newInterval还没插入,则将newInterval插入result,之后再插入intervals[i] 如果intervals[i]和newInterval有交集,则更新newInterval的start.end 代码: vector<Interva…