An undirected, connected graph of N nodes (labeled 0, 1, 2, ..., N-1) is given as graph. graph.length = N, and j != i is in the list graph[i] exactly once, if and only if nodes i and j are connected. Return the length of the shortest path that visits…

设计最短路径 用bfs 天然带最短路径 每一个状态是 当前的阶段 和已经访问过的节点 下面是正确但是超时的代码 class Solution: def shortestPathLength(self, graph): """ :type graph: List[List[int]] :rtype: int """ N=len(graph) Q=collections.deque([(1 << x, x) for x in range(…

题目链接:https://leetcode.com/problems/shortest-path-visiting-all-nodes/ 题意:已知一条无向图,问经过所有点的最短路径是多长,边权都为1,每个点可能经过多次. 这道题写的时候想简单了,把它当成树的直径来做了,求出一条最长路径len(len上的点只经过一次),2*(点数-1)-len即为答案,竟然过了,后来看了看讨论区发现这不是正解,而且我也没办法证明,感觉是蒙对的.贴下代码: class Solution { public: voi…

题解 题意 给出一个无向图,求遍历所有点的最小花费 分析 1.BFS,设置dis[status][k]表示遍历的点数状态为status,当前遍历到k的最小花费,一次BFS即可 2.使用DP 代码 //BFS class Solution { public: int dis[1<<12][12]; int shortestPathLength(vector<vector<int>>& graph) { int n=graph.size(); if(n==0) re…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/shortest-path-visiting-all-nodes/description/ 题目描述: An undirected, connected graph of N nodes (labeled 0, 1, 2, ..., N-1) is given as graph. graph.length = N,…

An undirected, connected graph of N nodes (labeled 0, 1, 2, ..., N-1) is given as graph. graph.length = N, and j != i is in the list graph[i] exactly once, if and only if nodes i and j are connected. Return the length of the shortest path that visits…

An undirected, connected graph of N nodes (labeled 0, 1, 2, ..., N-1) is given as graph. graph.length = N, and j != i is in the list graph[i] exactly once, if and only if nodes i and j are connected. Return the length of the shortest path that visits…

2018-10-06 22:04:38 问题描述: 问题求解: 本题要求是求遍历所有节点的最短路径,由于本题中是没有要求一个节点只能访问一次的,也就是说可以访问一个节点多次,但是如果表征两次节点状态呢?可以使用(curNode, VisitedNode)来进行表征,如果两次的已经访问的节点相同那么就没有必要再进行访问了,最终的状态就是所有节点都访问过了. 另外,由于起点对结果是有影响的,因此在最开始需要将所有的节点都压栈. public int shortestPathLength(int[][…

题目链接:http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=GRL_1_C All Pairs Shortest Path Input An edge-weighted graph G (V, E). |V| |E| s0 t0 d0 s1 t1 d1 : s|E|−1 t|E|−1 d|E|−1 |V| is the number of vertices and |E| is the number of edges in G. T…

原题链接在这里:https://leetcode.com/problems/shortest-path-in-binary-matrix/ 题目: In an N by N square grid, each cell is either empty (0) or blocked (1). A clear path from top-left to bottom-right has length k if and only if it is composed of cells C_1, C_2,…

We are given a 2-dimensional grid. "." is an empty cell, "#" is a wall, "@" is the starting point, ("a", "b", ...) are keys, and ("A", "B", ...) are locks. We start at the starting poin…

题目 非常简单的BFS 暴搜 struct Node { int x; int y; int k; int ans; Node(){} Node(int x,int y,int k,int ans) { this->x=x; this->y=y; this->k=k; this->ans=ans; } }; class Solution { public: int dir[4][2]={{0,-1},{0,1},{1,0},{-1,0}}; int vis[105][105]; i…

LeetCode:访问所有节点的最短路径[847] 题目描述 给出 graph 为有 N 个节点(编号为 0, 1, 2, ..., N-1)的无向连通图. graph.length = N,且只有节点 i 和 j 连通时,j != i 在列表 graph[i] 中恰好出现一次. 返回能够访问所有节点的最短路径的长度.你可以在任一节点开始和停止,也可以多次重访节点,并且可以重用边. 示例 1: 输入:[[1,2,3],[0],[0],[0]] 输出:4 解释:一个可能的路径为 [1,0,2,0,…

题目如下: Consider a directed graph, with nodes labelled 0, 1, ..., n-1.  In this graph, each edge is either red or blue, and there could be self-edges or parallel edges. Each [i, j] in red_edges denotes a red directed edge from node i to node j.  Simila…

原题链接在这里:https://leetcode.com/problems/shortest-path-with-alternating-colors/ 题目: Consider a directed graph, with nodes labelled 0, 1, ..., n-1.  In this graph, each edge is either red or blue, and there could be self-edges or parallel edges. Each [i,…

Problem Description This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que cambiar un poco el algoritmo. If you do not understand a word of this paragraph, just move on.The Nya graph is an un…

Description This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que cambiar un poco el algoritmo. If you do not understand a word of this paragraph, just move on. The Nya graph is an undirecte…

Given a binary tree, find the length of the longest path where each node in the path has the same value. This path may or may not pass through the root. Note: The length of path between two nodes is represented by the number of edges between them. Ex…

1.概述 路由协议OSPF全称为Open Shortest Path First,也就开放的最短路径优先协议,因为OSPF是由IETF开发的,所以所有厂商都可以用. OSPF的流量使用IP协议号. OSPF对网络没有跳数限制,支持 Classless Interdomain Routing (CIDR)和Variable-Length Subnet Masks (VLSMs),没有自动汇总功能,可以手动汇总. OSPF并不会周期性更新路由表,而采用增量更新,即只在路由有变化时,才会发送更新,并且…

The Shortest Path in Nya Graph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 13445    Accepted Submission(s): 2856 Problem Description This is a very easy problem, your task is just calculate…

The Shortest Path in Nya Graph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 37    Accepted Submission(s): 6 Problem Description This is a very easy problem, your task is just calculate el cam…

转自:Pavel's Blog Now let's say we want to find the LCA for nodes 4 and 9, we will need to traverse the whole tree to compare each node so that we can locate the nodes. Now considering that we start the traversal with the left branch (pre-order travers…

(THIS BLOG WAS ORIGINALLY WRTITTEN IN CHINESE WITH LINK: http://www.cnblogs.com/waytofall/p/3732920.html) Foreword: Floyd-Warshall is a classical dynamical programming algorithm for deriving shortest paths between each pair of nodes on a graph. It ha…

Problem Description This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que cambiar un poco el algoritmo. If you do not understand a word of this paragraph, just move on.The Nya graph is an un…

Description This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que cambiar un poco el algoritmo. If you do not understand a word of this paragraph, just move on.  The Nya graph is an undirect…

The Shortest Path in Nya Graph Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 13070    Accepted Submission(s): 2794 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4725 Description: This is a ve…

Description This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que cambiar un poco el algoritmo. If you do not understand a word of this paragraph, just move on.        The Nya graph is an un…

题目描述 Bobo has a directed graph G with n vertex labeled by 1,2,3,..n. Let D(i,j) be the number of edges from vertex i to vertex j on the shortest path. If the shortest path does not exist,then D(i,j)=n. Bobo would like to find the sum of  D(i,j)*D(i,j…

HDU - 4725 The Shortest Path in Nya Graph http://acm.hdu.edu.cn/showproblem.php?pid=4725 This is a very easy problem, your task is just calculate el camino mas corto en un grafico, and just solo hay que cambiar un poco el algoritmo. If you do not und…

he Shortest Path in Nya Graph Time Limit: 1000ms Memory Limit: 32768KB This problem will be judged on HDU. Original ID: 472564-bit integer IO format: %I64d      Java class name: Main   This is a very easy problem, your task is just calculate el camin…