The set S originally contains numbers from 1 to n. But unfortunately, due to the data error, one of the numbers in the set got duplicated to another number in the set, which results in repetition of one number and loss of another number. Given an arr…

The set S originally contains numbers from 1 to n. But unfortunately, due to the data error, one of the numbers in the set got duplicated to another number in the set, which results in repetition of one number and loss of another number. Given an arr…

Question 645. Set Mismatch Solution 思路: 遍历每个数字,然后将其应该出现的位置上的数字变为其相反数,这样如果我们再变为其相反数之前已经成负数了,说明该数字是重复数,将其将入结果res中,然后再遍历原数组,如果某个位置上的数字为正数,说明该位置对应的数字没有出现过,加入res中即可 Java实现: public int[] findErrorNums(int[] nums) { /* int a = 0; for (int i : nums) { if (nu…

题目: 448. Find All Numbers Disappeared in an Array Given an array of integers where 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once. Find all the elements of [1, n] inclusive that do not appear in this array. Could…

645. Set Mismatch 1.Problem The set S originally contains numbers from 1 to n. But unfortunately, due to the data error, one of the numbers in the set got duplicated to another number in the set, which results in repetition of one number and loss of…

problem 645. Set Mismatch 题意: solution1: 统计每个数字出现的次数了,然后再遍历次数数组,如果某个数字出现了两次就是重复数,如果出现了0次,就是缺失数. 注意:如何统计每个数字出现的次数: class Solution { public: vector<int> findErrorNums(vector<int>& nums) { vector<, ), cnt(nums.size(), ); ]; ; i<nums.siz…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Hash方法 直接计算 日期 题目地址: https://leetcode.com/problems/set-mismatch/description/ 题目描述 The set S originally contains numbers from 1 to n. But unfortunately, due to the data error, o…

645. 错误的集合 集合 S 包含从1到 n 的整数.不幸的是,因为数据错误,导致集合里面某一个元素复制了成了集合里面的另外一个元素的值,导致集合丢失了一个整数并且有一个元素重复. 给定一个数组 nums 代表了集合 S 发生错误后的结果.你的任务是首先寻找到重复出现的整数,再找到丢失的整数,将它们以数组的形式返回. 示例 1: 输入: nums = [1,2,2,4] 输出: [2,3] 注意: 给定数组的长度范围是 [2, 10000]. 给定的数组是无序的. class Solution…

static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { public: vector<int> findErrorNums(vector<int>& nums) { int sz=nums.size(); vector<,); for(int i:nums) help[i]++; help[]=; vector<int>…

［抄题］: he set S originally contains numbers from 1 to n. But unfortunately, due to the data error, one of the numbers in the set got duplicated to another number in the set, which results in repetition of one number and loss of another number. Given a…