FZU 2171 线段树区间更新求和

【FZU 2171 线段树区间更新求和】的更多相关文章

FZU 2171 线段树区间更新求和

很模板的题在建树的时候输入求和后更新 #include<stdio.h> #include<string.h> #include<algorithm> #include<math.h> #include<map> using namespace std; ///线段树成段更新 struct node { int l; int r; int total; int mark; }; node a[100050*4]; int c[100050]…

HDU 1698 线段树区间更新求和

一开始这条链子全都是1 #include<stdio.h> #include<string.h> #include<algorithm> #include<math.h> #include<map> using namespace std; ///线段树区间更新 #define MAX 100050 struct node { int left; int right; int mark; int total; }; node tree[MAX*…

poj 3468 A Simple Problem with Integers (线段树区间更新求和lazy思想)

A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 75541 Accepted: 23286 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of…

[POJ] 3468 A Simple Problem with Integers [线段树区间更新求和]

A Simple Problem with Integers Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum o…

线段树区间更新&&求和poj3486

给出了一个序列,你需要处理如下两种询问. ≤ c ≤ ). "Q a b" 询问[a, b]区间中所有值的和. Input 第一行包含两个整数N, Q. ≤ N,Q ≤ . 第二行包含n个整数,表示初始的序列A (- ≤ Ai ≤ ). 接下来Q行询问, Sample Input Q Q Q C Q Sample Output #include<iostream> #include<stdio.h> #include<cstring> using n…

HDU 1689 Just a Hook （线段树区间更新+求和）

Just a Hook Problem Description In the game of DotA, Pudge's meat hook is actually the most horrible thing for most of the heroes. The hook is made up of several consecutive metallic sticks which are of the same length. Now Pudge wants to do some ope…