class Solution: def lengthOfLastWord(self, s): """ :type s: str :rtype: int """ l = [] for i in s[::-1].lstrip(): if i != ' ': l.append(i) else: break return len(l) w = Solution() print(w.lengthOfLastWord("hello world&qu…
[ 问题: ] Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string. If the last word does not exist, return 0. 给你一个字符串,设法获取它最后一个单词的长度.假设这个单词不存在,则返回0. [ 分析 : ] A word is defined…
Given a string s consists of upper/lower-case alphabets and empty space characters' ', return the length of last word in the string. If the last word does not exist, return 0. Note: A word is defined as a character sequence consists of non-space char…