Leetcode908.Smallest Range I最小差值1】的更多相关文章

给定一个整数数组 A,对于每个整数 A[i],我们可以选择任意 x 满足 -K <= x <= K,并将 x 加到 A[i] 中. 在此过程之后,我们得到一些数组 B. 返回 B 的最大值和 B 的最小值之间可能存在的最小差值. 示例 1: 输入:A = [1], K = 0 输出:0 解释:B = [1] 示例 2: 输入:A = [0,10], K = 2 输出:6 解释:B = [2,8] 示例 3: 输入:A = [1,3,6], K = 3 输出:0 解释:B = [3,3,3] 或…
Given an array A of integers, for each integer A[i] we may choose any x with -K <= x <= K, and add x to A[i]. After this process, we have some array B. Return the smallest possible difference between the maximum value of B and the minimum value of B…
Given an array A of integers, for each integer A[i] we need to choose either x = -K or x = K, and add x to A[i] (only once). After this process, we have some array B. Return the smallest possible difference between the maximum value of B and the mini…
You have k lists of sorted integers in ascending order. Find the smallest range that includes at least one number from each of the k lists. We define the range [a,b] is smaller than range [c,d] if b-a < d-c or a < c if b-a == d-c. Example 1: Input:[…
You have k lists of sorted integers in ascending order. Find the smallest range that includes at least one number from each of the k lists. We define the range [a,b] is smaller than range [c,d] if b-a < d-c or a < c if b-a == d-c. Example 1: Input:[…
Given an array A of integers, for each integer A[i] we need to choose either x = -K or x = K, and add x to A[i] (only once). After this process, we have some array B. Return the smallest possible difference between the maximum value of B and the mini…
Given an array A of integers, for each integer A[i] we may choose any x with -K <= x <= K, and add x to A[i]. After this process, we have some array B. Return the smallest possible difference between the maximum value of B and the minimum value of B…
You have k lists of sorted integers in ascending order. Find the smallest range that includes at least one number from each of the k lists. We define the range [a,b] is smaller than range [c,d] if b-a < d-c or a < c if b-a == d-c. Example 1: Input:[…
LuoguP4234_最小差值生成树_LCT 题意: 给出一个无向图,求最大的边权减最小的边权最小的一棵生成树. 分析: 可以把边权从大到小排序,然后类似魔法森林那样插入. 如果两点不连通,直接连上,否则找到两点间最大的边权替换. 如果生成一棵树了就更新答案. LCT维护边权的最大值即可. 代码: // luogu-judger-enable-o2 #include <stdio.h> #include <string.h> #include <algorithm> u…
题目链接:http://118.190.20.162/view.page?gpid=T68 问题描述 试题编号: 201712-1 试题名称: 最小差值 时间限制: 1.0s 内存限制: 256.0MB 问题描述: 问题描述 给定n个数,请找出其中相差(差的绝对值)最小的两个数,输出它们的差值的绝对值. 输入格式 输入第一行包含一个整数n. 第二行包含n个正整数,相邻整数之间使用一个空格分隔. 输出格式 输出一个整数,表示答案. 样例输入 5 1 5 4 8 20 样例输出 1 样例说明 相差最…