转载:43. Multiply Strings 题目描述 就是两个数相乘,输出结果,只不过数字很大很大,都是用 String 存储的.也就是传说中的大数相乘. 解法一 我们就模仿我们在纸上做乘法的过程写出一个算法. 个位乘个位,得出一个数,然后个位乘十位,全部乘完以后,就再用十位乘以各个位.然后百位乘以各个位,最后将每次得出的数相加.十位的结果要补 1 个 0 ,百位的结果要补两个 0 .相加的话我们可以直接用之前的大数相加.直接看代码吧. public String multiply(Stri…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 给出两个字符串,返回对应数字想乘后的字符串,由于这个字符串可能很大,所以不能采用一般的乘法,这里用的方法是模拟手工的乘法运算,算法 本身很简单,就是当时写的时候有些很小的细节搞错了,找了…
Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&…
Given two non-negative integers num1 and num2represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&q…
Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. Converting the input string to integer is NOT allowed. You should NOT use internal library su…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 要求:字符串表示的数字可能无穷大,并且非负. class Solution { private: vector<string> tempStrs; public: string add…
http://www.cnblogs.com/TenosDoIt/p/3735309.html https://blog.csdn.net/fly_yr/article/details/48055617 class Solution { public: string multiply(string num1, string num2) { int len1 = num1.length(); int len2 = num2.length(); vector<); ; 第一轮乘出来的结果只有len1…
Given two non-negative numbers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…
Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative.     各个位相乘,保存在数组中,最后再处理进位. 如 123*456     4,5,6      8,10,12         12,15,18…
题目要求:Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 分析: 参考网址:http://blog.csdn.net/pickless/article/details/9235907 利用竖式的思想,…
题目: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题意给两个字符串表示的数字,计算他们的乘积. 其实就是手写一个大数乘法,先翻转字符串便于从低位开始计算. 模拟乘法的运算过程,把中间结果存在data中,最后在考虑data的进位并…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这道题让我们求两个字符串数字的相乘,输入的两个数和返回的数都是以字符串格式储存的,这样做的原因可能是这样可以计算超大数相乘,可以不受int或long的数值范围的约束,那么我们该如何来计算…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题意:计算字符串对应数字的乘积.参考JustDoIT的博客. 思路:先用一维向量存放计算的中间值,中间值存放对应位置乘积的和(暂不考虑进位的情况):然后针对进位的情况,进行计算:注意要跳…
题目链接: https://leetcode.com/problems/multiply-strings/?tab=Description     求解大数相乘问题   按照上图所示,进行嵌套循环计算.每次计算出两个位置上的数字,并且对其求和进行更新操作. 下面这个讲解很赞!!! https://discuss.leetcode.com/topic/30508/easiest-java-solution-with-graph-explanation/3      参考代码:  package l…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. string multiply(string& num, char ch){ '; string s; ; int x; ; i>=; i--){ x = (num[i]-') *…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 第一眼看到这个题目,潜意识里觉得直接将字符串转换为数字相乘,然后将结果再转换为字符串,难道这题考的是字符串与数值之间的转换? 细看,发现数字可能非常大,那么问题来了:这个数据类型怎么定义…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 解题思路一: BigInteger!!! JAVA实现如下: import java.math.BigInteger; public class Solution { static pu…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 思路:直观思路,就是模拟乘法过程.注意进位.我写的比较繁琐. string multiply(string num1, string num2) { vector<int> v1, v…
网址:https://leetcode.com/problems/multiply-strings/submissions/ 参考:https://leetcode.com/problems/multiply-strings/discuss/17605/Easiest-JAVA-Solution-with-Graph-Explanation 把乘法分解为最最基础的加法,从后往前循环. class Solution { public: string multiply(string num1, st…
1. 原始题目 给定两个以字符串形式表示的非负整数 num1 和 num2,返回 num1 和 num2 的乘积,它们的乘积也表示为字符串形式. 示例 1: 输入: num1 = "2", num2 = "3" 输出: "6" 示例 2: 输入: num1 = "123", num2 = "456" 输出: "56088" 说明: num1 和 num2 的长度小于110. num1 和…
给定两个以字符串表示的非负整数 num1 和 num2,返回 num1 和 num2 的乘积.注意:    num1 和 num2 的长度均小于110.    num1 和 num2 均只包含数字 0-9.    num1 和 num2 均不以零开头.    你不能使用任何内置的大整数库或直接将输入转换为整数.详见:https://leetcode.com/problems/multiply-strings/description/ Java实现: class Solution { public…
题目: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 思路比较简单,不多说啦 几个需要注意的点: 1. 高位多个为0的,需要进行判断 2. 如果乘数为0的话,可以直接跳过,能节省不少时间 3. string 的两个使用 1) 创建有…
题目描述: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 解题思路: 设置数组记录单个位置相乘的结果,最后负责相加进位. 代码如下: public class Solution { public String multiply(St…
DescriptionHintsSubmissionsDiscussSolution   Pick One Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Out…
给定两个以字符串形式表示的非负整数 num1 和 num2,返回 num1 和 num2 的乘积,它们的乘积也表示为字符串形式. 示例 1: 输入: num1 = "2", num2 = "3" 输出: "6" 示例 2: 输入: num1 = "123", num2 = "456" 输出: "56088" 说明: num1 和 num2 的长度小于110. num1 和 num2 只包…
判断两个字符串是否同构 hs,ht就是每个字符出现的顺序 "egg" 与"add"的数字都是122 "foo"是122, 而"bar"是123 class Solution { public: bool isIsomorphic(string s, string t) { ] = {}; ] = {}; if (s.size() != t.size()) return false; ; ;i<s.size(); ++i)…
感觉是大数相乘算法里面最能够描述.模拟演算过程的思路 class Solution { public String multiply(String num1, String num2) { if(num1.charAt(0) == '0' || num2.charAt(0) == '0'){ return "0"; } int len1 = num1.length(); int len2 = num2.length(); int len = len1+len2; int[] arr =…
Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2. Note: The length of both num1 and num2 is < 5100. Both num1 and num2 contains only digits 0-9. Both num1 and num2 does not contain any leading zero.…
43. 字符串相乘 43. Multiply Strings 题目描述 给定两个以字符串形式表示的非负整数 num1 和 num2,返回 num1 和 num2 的乘积,它们的乘积也表示为字符串形式. LeetCode43. Multiply Strings中等 示例 1: 输入: num1 = "2", num2 = "3" 输出: "6" 示例 2: 输入: num1 = "123", num2 = "456&q…