[Leetcode] reverse integer 反转整数】的更多相关文章

Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought throug…
Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 题意: 给定一个10进制整数,翻转它. Solution1: directly do the simulation. Two tricky parts to be hand…
描述: 给定32位整数,反转,如321转成123. 解决: 关键是溢出检测: int reverse(int x) { ; int temp; while (x) { temp = ret * + x % ; != ret) ; ret = temp; x /= ; } return ret; } 看了下其他答案,还有一些思路: 先声明个long,看最后是否溢出,这样只有long是64位时可以,或者用int64_t. 还有先转字符串反转再转数字的.…
Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought throu…
[抄题]: 将一个整数中的数字进行颠倒,当颠倒后的整数溢出时,返回 0 (标记为 32 位整数).   样例 给定 x = 123,返回 321 给定 x = -123,返回 -321 [暴力解法]: 时间分析: 空间分析: [优化后]: 时间分析: 空间分析: [奇葩输出条件]: [奇葩corner case]: 负数.末尾有0均可用该方法处理 [思维问题]: [一句话思路]: 分离一位数.一边变长 另一边变短 [输入量]:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不…
Reverse digits of an integer. Returns 0 when the reversed integer overflows (signed 32-bit integer). Have you met this question in a real interview?     Example Given x = 123, return 321 Given x = -123, return -321 LeetCode上的原题,请参见我之前的博客Reverse Integ…
Reverse Integer Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 若反转的数溢出,直接返回0 可以用计算结果来判断溢出,也可以用因数来判断 Java代码实现: public class ReverseInteger { public static int reverseInt(int x){ if (x == 0) { return 0; } int…
Reverse Integer Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 click to show spoilers. SOLUTION 1: 注意越界后返回0.先用long来计算,然后,把越界的处理掉. public class Solution { public int reverse(int x) { long ret = 0; while (x !…
题目等级:Easy 题目描述: Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21    题意:给出一个 32 位的有符号整数,你需要将这个整数中每位上的数字进行反转. 解题思路:   本题很简单,我们给出以下两种方法.  …
题目 Given a 32-bit signed integer, reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123,return -321 Example3: x = 120, return 21 思路 问题的关键在于对溢出的判断. 思路1:用long或者long long 直接用long或者long long计算,这样就保证不会溢出,再判断反转后的数字是否溢出. 思路2:stoi()…