题目链接:https://vjudge.net/problem/UVA-822 翻译摘自:<算法禁赛入门经典> 题目大意 你的任务是模拟一个客户中心运作情况.客服请求一共有n(1 ≤ n ≤ 20)种主题,每种主 题用 5 个整数描述:tid, num, t0, t, dt,其中 tid 为主题的唯一标识符,num为该主题的请求个 数,t0 为第一个请求的时刻,t 为处理一个请求的时间,dt 为相邻两个请求之间的间隔(为了简化情况,假定同一个主题的请求按照相同的间隔到达). 客户中心有m(1…

版权声明:本文为博主原创文章.未经博主同意不得转载. https://blog.csdn.net/u013840081/article/details/26180081 题目例如以下: Team Queue  Queues and Priority Queues are data structures which are known to most computer scientists. TheTeam Queue, however, is not so well known, though…

Team Queue Time Limit:                                                        3000MS                           Memory Limit: Unknown   64bit IO Format:                            %lld & %llu                         Submit                             …

The Summer Training Summary-- the first A - vector的使用 UVa 101 关于vector 的几个注意点 vector p p.push_back(); 送入数据 p.insert() 指定位置指定元素,指定位置n个相同元素,指定位置 区间元素 p.assign(); 赋值 p.pop_back(); 移除最后一个数据 p.erase(); 删除指定位置 或者 指定区间数据 p.resize();改变容器大小相当于保留N个元素 p.clear()…

UVA.540 Team Queue (队列) 题意分析 有t个团队正在排队,每次来一个新人的时候,他可以插入到他最后一个队友的身后,如果没有他的队友,那么他只能插入到队伍的最后.题目中包含以下操作: 1.ENQUEUE x :表示编号为x的入队: 2.DEQUEUE:长队的队首出队. 3.STOP:停止模拟 并且对于每一个DEQUEUE操作,输出队首的编号. 如果我们直接用一个队列来模拟的话,是无法实现的,原因在于,我们无法向队列中间插入元素.那么题目中还有一条重要的性质,那么就是:可以插入到…

首发:https://mp.csdn.net/mdeditor/80294426 例题5-6 团体队列(Team Queue,UVa540) 有t个团队的人正在排一个长队.每次新来一个人时,如果他有队友在排队,那么这个 新人会插队到最后一个队友的身后.如果没有任何一个队友排队,则他会排到长队的队尾. 输入每个团队中所有队员的编号,要求支持如下3种指令(前两种指令可以穿插进 行). ENQUEUEx:编号为x的人进入长队. DEQUEUE:长队的队首出队. STOP:停止模拟. 对于每个DEQUE…

Trees are fundamental in many branches of computer science (Pun definitely intended). Current state- of-the art parallel computers such are based on fat trees . Quad- and octal-trees are fundamental to many algorithms in computer graphics. This probl…

题目代号:UVA 540 题目链接:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=481 题目描述: Team Queue Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2645 Ac…

The Dole Queue 题解: 这里写一个走多少步,返回位置的函数真的很重要,并且,把顺时针和逆时针写到了一起,也真的很厉害,需要学习 代码: #include<stdio.h> #define maxn 25 int n, k, m, a[maxn]; int go(int p,int d,int t) { while(t--){ do{p=(p+d-1+n)%n+1;}while(a[p]==0); } return p; } int main() { while(scanf(&qu…

用一个队列模拟,还有一个数组cnt记录9个优先级的任务的数量,每次找到当前最大优先级的任务然后出队,并及时更新cnt数组. #include <iostream> #include <cstring> #include <algorithm> #include <cstdio> #include <queue> using namespace std; struct Task { int pos, pri; Task(, ):pos(pos),…

题意:给出t个团体,这t个团体排在一起,每次新来一个x排队,如果在整个的团体队列中,有x的队友,那么x排在它的队友的后面,如果他没有队友,则排在长队的队尾 求给出的每一个出队命令,输出出队的人的编号 紫书上的思路:有两个队列,一个是每一个团体内部形成的队列,还有一个是这t个团体又构成的队列 #include<iostream> #include<cstdio> #include<cstring> #include <cmath> #include<st…

双向约瑟夫环. 数据规模只有20,模拟掉了.(其实公式我还是不太会推,有空得看看) 值得注意的是两个方向找值不是找到一个去掉一个,而是找到后同时去掉. 还有输出也很坑爹! 在这里不得不抱怨下Uva的oj,少了个s,少了个空行什么的都不会显示pe,就给个wa,让人还以为算法有问题.原本以为Uva没有pe,然后据说这边的输出空行如果不对的话就会显示pe... 代码: #include <cstdio> #include <cstring> const int maxn = 22; in…

题意: 每个人都属于一个团体,在排队的时候,如果他所在的团体有人在队伍中,则他会站到这个团体的最后.否则站到整个队伍的队尾. 输出每次出队的人的编号. 分析: 容易看出,长队中,在同一个团体的人是排在一起的. 所以用两个队列模拟即可,一个队列保留团体的编号,另外一个队列数组存放的是团体中每个人的编号. #include <cstdio> #include <queue> #include <map> using namespace std; + ; map<int…

题意:给你n个操做,判断是那种数据结构. #include<iostream> #include<cstdio> #include<cstdlib> #include<stack> #include<queue> using namespace std; int n; ],u[]; int ck_q() { //cout<<"!!"<<endl; queue<int>s; ; i<n;…

类型:循环走步 #include <iostream> #include <sstream> #include <cstdio> #include <cstring> #include <cmath> #include <string> #include <vector> #include <set> #include <cctype> #include <algorithm> #inc…

思路:使用优先队列,按队伍出现的时刻和自身出现的时刻定义优先级,同时记录此时刻队列里是否有自己队伍的人,一开始没注意,wa了两发. #include<map> #include<queue> #include<cstdio> #include<string> #include<cstring> #include<iostream> #include<algorithm> using namespace std; const…

The only printer in the computer science students' union is experiencing an extremely heavy workload. Sometimes there are a hundred jobs in the printer queue and you may have to wait for hours to get a single page of output. Because some jobs are mor…

Given is an ordered deck of    n    cards numbered 1 to    n    with card 1 at the top and card    n    at the bottom. The following operation is performed as long as there are at least two cards in the deck: Throw away the top card and move the card…

Ducci Sequence Description   A Ducci sequence is a sequence of n-tuples of integers. Given an n-tuple of integers (a1, a2, ... , an), the next n-tuple in the sequence is formed by taking the absolute differences of neighboring integers: ( a1, a2, ...…

传送门:https://uva.onlinejudge.org/external/121/12100.pdf 题意:队列中待打印的任务(1 <= n <= 100)带有优先级(1-9), 打印步骤为每次从队首拿出一个, 如果队列中没有优先级比该任务高的, 打印这个任务; 若有优先级高的, 把这个任务放到队尾,  并打印优先级最高的. 每打印一次耗时1分钟, 求给定任务什么时候打印. 水题A半天    不愧是弱渣.......... 最坏的情况需要maxn*maxn的空间........ fro…

The only printer in the computer science students' union is experiencing an extremely heavy workload. Sometimes there are a hundred jobs in the printer queue and you may have to wait for hours to get a single page of output. Because some jobs are mor…

On some special occasions Nadia’s company provide very special lunch for all employees of the company. Before the food is served all of the employees must stand in a queue in front of the food counter. The company applied a rule for standing in the q…

题目 题目     分析 练习STL     代码 #include <bits/stdc++.h> using namespace std; int main() { int t; scanf("%d",&t); while(t--) { int n,m,a[105],cnt=0; queue <int> que; priority_queue <int> Big; scanf("%d%d",&n,&m)…

Team Queue Descriptions: Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front of the Mensa…

又是一道比较复杂的模拟题.题中有两种队列,一种是总队列,从前向后.其他的是各个团体的小队列,因为入队的人如果有队友的话,会优先进入团体队列. 所以我们先设置两个队列和一个map,设置map倒是可以不用担心开多大数组这样的问题.然后开两个队列,一个是基本的q1,另一个是q2[1010] 一般的STL容器如string vector deque都是有两种直接初始化的方法(不严谨)一种是a(maxn)这个和一维数组差不多,直接赋给里面多少元素,另一种就是a[maxn]这个差不多是一个容器的数组,每一个…

[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 用队列和multiset就能完成模拟 [代码] #include <bits/stdc++.h> using namespace std; int n, m; queue <pair<int,int> > dl; multiset <int,greater<int> > mset; int main() { //freopen("F:\\rush.txt",…

[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 用两个队列模拟就好. 记录某个队在不在队列里面. 模拟 [错的次数] 在这里输入错的次数 [反思] 在这里输入反思 [代码] #include <bits/stdc++.h> using namespace std; const int N = 1e3; int t; queue <int> team[N+10]; queue <int> dl; map <int,int> dic; boo…

  Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front of the Mensa is a team queue, for e…

The only printer in the computer science students' union is experiencing an extremely heavy workload. Sometimes there are a hundred jobs in the printer queue and you may have to wait for hours to get a single page of output. Because some jobs are mor…

 In a serious attempt to downsize (reduce) the dole queue, The New National Green Labour Rhinoceros Party has decided on the following strategy. Every day all dole applicants will be placed in a large circle, facing inwards. Someone is arbitrarily ch…