In this problem, a rooted tree is a directed graph such that, there is exactly one node (the root) for which all other nodes are descendants of this node, plus every node has exactly one parent, except for the root node which has no parents. The give…

In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one additional edge added. The added edge has two different v…

In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one additional edge added. The added edge has two different v…

lc 684 Redundant Connection 684 Redundant Connection In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one addi…

In this problem, a rooted tree is a directed graph such that, there is exactly one node (the root) for which all other nodes are descendants of this node, plus every node has exactly one parent, except for the root node which has no parents. The give…

In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one additional edge added. The added edge has two different v…

原题链接在这里:https://leetcode.com/problems/redundant-connection-ii/ 题目: In this problem, a rooted tree is a directed graph such that, there is exactly one node (the root) for which all other nodes are descendants of this node, plus every node has exactly…

In this problem, a rooted tree is a directed graph such that, there is exactly one node (the root) for which all other nodes are descendants of this node, plus every node has exactly one parent, except for the root node which has no parents. The give…

Leetcode之并查集专题-684. 冗余连接(Redundant Connection) 在本问题中, 树指的是一个连通且无环的无向图. 输入一个图,该图由一个有着N个节点 (节点值不重复1, 2, ..., N) 的树及一条附加的边构成.附加的边的两个顶点包含在1到N中间,这条附加的边不属于树中已存在的边. 结果图是一个以边组成的二维数组.每一个边的元素是一对[u, v] ,满足 u < v,表示连接顶点u 和v的无向图的边. 返回一条可以删去的边,使得结果图是一个有着N个节点的树.如果有…

We are given a "tree" in the form of a 2D-array, with distinct values for each node. In the given 2D-array, each element pair [u, v] represents that v is a child of u in the tree. We can remove exactly one redundant pair in this "tree"…

In this problem, a rooted tree is a directed graph such that, there is exactly one node (the root) for which all other nodes are descendants of this node, plus every node has exactly one parent, except for the root node which has no parents. The give…

In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one additional edge added. The added edge has two different v…

https://leetcode.com/problems/redundant-connection/description/ Use map to do Union Find. class Solution { public: vector<int> findRedundantConnection(vector<vector<int>>& edges) { unordered_map<int,int> parent; for (const auto…

https://leetcode.com/problems/redundant-connection/ 一个无向图,n个顶点有n条边,输出一条可以删除的边,删除后使得图成为一棵树.可以使用并查集解决. class Solution { public: ]; void initfather() { ; i<=; i++) father[i]=i; } int findFather(int x) { if(father[x]!=x) father[x] = findFather(father[x])…

In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one additional edge added. The added edge has two different v…

题目: In this problem, a tree is an undirected graph that is connected and has no cycles. The given input is a graph that started as a tree with N nodes (with distinct values 1, 2, ..., N), with one additional edge added. The added edge has two differe…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 并查集 日期 题目地址:https://leetcode.com/problems/redundant-connection/description/ 题目描述 In this problem, a tree is an undirected graph that is connected and has no cycles. The given i…

A 2d grid map of m rows and n columns is initially filled with water. We may perform an addLand operation which turns the water at position (row, col) into a land. Given a list of positions to operate, count the number of islands after each addLand o…

There are N students in a class. Some of them are friends, while some are not. Their friendship is transitive in nature. For example, if A is a direct friend of B, and B is a direct friend of C, then A is an indirect friend of C. And we defined a fri…

Given a list accounts, each element accounts[i] is a list of strings, where the first element accounts[i][0] is a name, and the rest of the elements are emails representing emails of the account. Now, we would like to merge these accounts. Two accoun…

请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift    说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序        号 题名Title 难度     Difficulty  两数之…

Union Find算法基础 Union Find算法用于处理集合的合并和查询问题,其定义了两个用于并查集的操作: Find: 确定元素属于哪一个子集,或判断两个元素是否属于同一子集 Union: 将两个子集合并为一个子集 并查集是一种树形的数据结构,其可用数组或unordered_map表示: Find操作即查找元素的root,当两元素root相同时判定他们属于同一个子集:Union操作即通过修改元素的root(或修改parent)合并子集,下面两个图展示了id[6]由6修改为9的变化:   …

We have a grid of 1s and 0s; the 1s in a cell represent bricks.  A brick will not drop if and only if it is directly connected to the top of the grid, or at least one of its (4-way) adjacent bricks will not drop. We will do some erasures sequentially…

UnionFind就是acm中常用的并查集... 并查集常用操作 另外补充一下STL常用操作 相关问题: 547. Friend Circles 纯裸题噢... class Solution { public: ]; ]; void uf_init(int x) { ;i<=x;i++) root[i]=i; } int uf_find(int x) { if(x!=root[x]) root[x]=uf_find(root[x]); return root[x]; } void uf_unio…

最近接触了一下Oracle 11g R2 的RAC,发现变化很大. 所以在自己动手做实验之前还是先研究下它的新特性比较好. 一．    官网介绍 先看一下Oracle 的官网文档里对RAC 新特性的一点说明. Oracle Database 11g Release 2 (11.2.0.2) New Features in Oracle RAC http://download.oracle.com/docs/cd/E11882_01/rac.112/e16795/whatsnew.htm#CHDJ…

突然很想刷刷题,LeetCode是一个不错的选择,忽略了输入输出,更好的突出了算法,省去了不少时间. dalao们发现了任何错误,或是代码无法通过,或是有更好的解法,或是有任何疑问和建议的话,可以在对应的随笔下面评论区留言,我会及时处理,在此谢过了. 过程或许会很漫长,也很痛苦,慢慢来吧. 编号 题名 过题率 难度 1 Two Sum 0.376 Easy 2 Add Two Numbers 0.285 Medium 3 Longest Substring Without Repeating C…

［抄题］: Given a list accounts, each element accounts[i] is a list of strings, where the first element accounts[i][0] is a name, and the rest of the elements are emails representing emails of the account. Now, we would like to merge these accounts. Two…

Union Find算法基础 Union Find算法用于处理集合的合并和查询问题,其定义了两个用于并查集的操作: Find: 确定元素属于哪一个子集,或判断两个元素是否属于同一子集 Union: 将两个子集合并为一个子集 并查集是一种树形的数据结构,其可用数组或unordered_map表示: Find操作即查找元素的root,当两元素root相同时判定他们属于同一个子集:Union操作即通过修改元素的root(或修改parent)合并子集,下面两个图展示了id[6]由6修改为9的变化:   …

图基础 图(Graph)应用广泛,程序中可用邻接表和邻接矩阵表示图.依据不同维度,图可以分为有向图/无向图.有权图/无权图.连通图/非连通图.循环图/非循环图,有向图中的顶点具有入度/出度的概念. 面对图相关问题,第一步是将问题转为用图表示(邻接表/邻接矩阵),二是使用图相关算法求解. 相关LeetCode题: 997. Find the Town Judge  题解 1042. Flower Planting With No Adjacent  题解 图的遍历(DFS/BFS) 图的遍历/搜索…

Two strings X and Y are similar if we can swap two letters (in different positions) of X, so that it equals Y. For example, "tars" and "rats" are similar (swapping at positions 0 and 2), and "rats" and "arts" are si…