Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Given…

基本问题 如何删除单链表中的倒数第n个节点? 常规解法 先遍历一遍单链表,计算出单链表的长度,然后,从单链表头部删除指定的节点. 代码实现 /** * * Description: 删除单链表倒数第n个节点,常规解法. * * @param head * @param n * @return ListNode */ public static ListNode removeNthFromEnd(ListNode head, int n) { if (head == null) return nu…

题目: 链表倒数第n个节点 找到单链表倒数第n个节点,保证链表中节点的最少数量为n. 样例 给出链表 3->2->1->5->null和n = 2,返回倒数第二个节点的值1. 解题: 某年408计算机考研题目 Java程序: /** * Definition for ListNode. * public class ListNode { * int val; * ListNode next; * ListNode(int val) { * this.val = val; * thi…

题目:输入1个链表,输出该链表倒数第k个节点,有头指针和尾指针.链表倒数第0个节点是链表的尾指针节点. 代码: /* 尾指针是倒数第0个,则倒数第k个是正数第len-k个,计算len */ #include<iostream> using namespace std; typedef struct node { int key; struct node* next; }List; List* head=NULL; List* tail=NULL; void create_list(void)…

找到单链表倒数第n个节点,保证链表中节点的最少数量为n. 样例 给出链表 3->2->1->5->null和n = 2,返回倒数第二个节点的值1. /** * Definition of ListNode * class ListNode { * public: * int val; * ListNode *next; * ListNode(int val) { * this->val = val; * this->next = NULL; * } * } */ cla…

Given a linked list, remove the n-th node from the end of list and return its head. Example: Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Given n w…

链表倒数第n个节点 找到单链表倒数第n个节点,保证链表中节点的最少数量为n. 思路:设置两个指针first,second指向head,first指针先向前走n,然后两个指针一起走,first指针走到末尾,second走到倒数第n个指针! 代码 /** * Definition of ListNode * class ListNode { * public: * int val; * ListNode *next; * ListNode(int val) { * this->val = val;…

Given a linked list, remove the nth node from the end of list and return its head. For example, Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5. Note: Given…

找到单链表倒数第n个节点,保证链表中节点的最少数量为n. 样例 给出链表 3->2->1->5->null和n = 2,返回倒数第二个节点的值1. 分析:设两个指针 p1和p2,p1遍历到n-1的位置,p2从头开始遍历 当p1到链表尾部的时候,p2刚好到倒数n的位置 注意鲁棒性的考虑 /** * Definition of ListNode * class ListNode { * public: * int val; * ListNode *next; * ListNode(in…

Leetcode算法系列(链表)之删除链表倒数第N个节点 难度:中等给定一个链表,删除链表的倒数第 n 个节点,并且返回链表的头结点.示例:给定一个链表: 1->2->3->4->5, 和 n = 2.当删除了倒数第二个节点后,链表变为 1->2->3->5.说明:给定的 n 保证是有效的.链接:https://leetcode-cn.com/problems/remove-nth-node-from-end-of-list Python实现 # Definiti…