Air Raid Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 6520 Accepted: 3877 Description Consider a town where all the streets are one-way and each street leads from one intersection to another. It is also known that starting from an i…
Consider a town where all the streets are one-way and each street leads from one intersection to another. It is also known that starting from an intersection and walking through town's streets you can never reach the same intersection i.e. the town's…
题目链接:https://vjudge.net/problem/HDU-1151 Air Raid Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5630 Accepted Submission(s): 3785 Problem Description Consider a town where all the streets a…
Air Raid Problem Description Consider a town where all the streets are one-way and each street leads from one intersection to another. It is also known that starting from an intersection and walking through town's streets you can never reach the same…
http://acm.hdu.edu.cn/showproblem.php?pid=1151 增广路的变种2:DAG图的最小路径覆盖=定点数-最大匹配数 #include<iostream> #include<stdio.h> #include<string.h> #include<stdlib.h> #include<math.h> using namespace std; ; int a[N][N]; int use[N]; int matc…
点击打开链接 有向无环图的最小路径覆盖 = 顶点数- 最大匹配 #include <queue> #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; const int maxn = 150; int g[maxn][maxn]; int n, m; int link[maxn]; bool used[…
#include <cstdio> #include <cstring> #include <cstdlib> #include <algorithm> using namespace std; #define MAXN 150 int n; //十字路口的数量 int m; //路的个数 int map[MAXN][MAXN]; int x[MAXN], y[MAXN]; int mark[MAXN]; int search(int a) { ; i &l…
Air Raid Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6528 Accepted Submission(s): 4330 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1151 Description: Consider a town where all the stree…
