题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1969 Pie Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 4513    Accepted Submission(s): 1819 Problem Description My birthday is coming up and trad…

My birthday is coming up and traditionally I’m serving pie. Not just one pie, no, I have a number N of them, of various tastes and of various sizes. F of my friends are coming to my party and each of them gets a piece of pie. This should be one piece…

Pie Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6320    Accepted Submission(s): 2383 Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I h…

Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I have a number N of them, of various tastes and of various sizes. F of my friends are coming to my party and each of them gets a piece of pie. This…

题目链接 Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I have a number N of them, of various tastes and of various sizes. F of my friends are coming to my party and each of them gets a piece of pie.…

Pie Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 16554    Accepted Submission(s): 5829   My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I have a number N of…

Pie Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3133    Accepted Submission(s): 1217 Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I h…

[分析] “虽然不是求什么最大的最小值(或者反过来)什么的……但还是可以用二分的,因为之前就做过一道小数型二分题(下面等会讲) 考虑二分面积,下界L=0,上界R=∑ni=1nπ∗ri2.对于一个中值x和一张半径r的饼来说,这张饼能够分出的最多分数显然是:⌊π∗r2x⌋,所以我们只需要求出∑ni=1⌊π∗ri2x⌋,判断其与f+1的关系即可 特别要注意的一点:π的大小!,因为r≤104r≤104,所以r2≤108r2≤108,又因为题目要求精确到三位小数,所以ππ就要精确到10-11,即π=3.1…

Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I have a number N of them, of various tastes and of various sizes. F of my friends are coming to my party and each of them gets a piece of pie. This…

Pie Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12138    Accepted Submission(s): 4280 Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I…

二分. #include <stdio.h> #include <math.h> ; ]; int main() { int case_n, n, f, m; double r, sum, l, mid, PI; int i; PI = acos(-); scanf("%d", &case_n); while (case_n--) { scanf("%d %d", &n, &f); sum = 0.0f; ; i<…

二分答案+验证(这题精度卡的比较死) #include<stdio.h> #include<math.h> #define eps 1e-7 ; double a[ff]; double pi = acos(-1.0); int main() { int sb; scanf("%d", &sb); while (sb--) { int m, n; scanf("%d%d", &m, &n); int i, j; ; ;…

题目大意:n块馅饼分给m+1个人,每个人的馅饼必须是整块的,不能拼接,求最大的. 解题思路: 1)用总饼的体积除以总人数,得到每个人最大可以得到的V.但是每个人手中不能有两片或多片拼成的一块饼. 代码如下: /* * 1969_2.cpp * * Created on: 2013年8月14日 * Author: Administrator */ #include <stdio.h> #include <math.h> #include <string.h> double…

1.题意:一项分圆饼的任务,一堆圆饼共有N个,半径不同,厚度一样,要分给F+1个人.要求每个人分的一样多,圆饼允许切但是不允许拼接,也就是每个人拿到的最多是一个完整饼,或者一个被切掉一部分的饼,要求你算出每人能分到的饼的体积最大值.输入数据依次给出,测试数据组数T,每组数据中,给出N,F,以及N个圆饼的半径.输出最大体积的数值,精确到小数点后四位. 2.分析:一看是这种输出就知道用二分写会很高效,这里对"能分出的最大体积值"进行二分.首先,这个值有界,最大值为总体积除以总人数的值,即Σ…

http://acm.hdu.edu.cn/showproblem.php?pid=1969 Pie Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 3303    Accepted Submission(s): 1280 Problem Description My birthday is coming up and traditio…

Pie Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7302    Accepted Submission(s): 2732 Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I h…

Pie Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 16056    Accepted Submission(s): 5654 Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I…

My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I have a number N of them, of various tastes and of various sizes. F of my friends are coming to my party and each of them gets a piece of pie. This should be one piece…

"Faux Amis"节目中经常提到"原始印欧语"(PIE)——"Proto-Indo-European". 我们说过,英语,法语中的"假朋友"基本都是"同源词"(cognate),而"同源词"的"源",常常是拉丁语等古代语言.但如果再往前追溯呢?就是"原始印欧语"啦. 到8000年前的黑海沿岸地区.由于农业发展,造成人口爆炸式增长,原始印欧人被迫…

Hie with the Pie Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 3160   Accepted: 1613 Description The Pizazz Pizzeria prides itself in delivering pizzas to its customers as fast as possible. Unfortunately, due to cutbacks, they can affo…

简单的大饼游戏,掌握pygame中直线以及圆弧的画法,以及对输入的响应. import math import pygame, sys from pygame.locals import * pygame.init() screen = pygame.display.set_mode((600, 500)) pygame.display.set_caption("The Pie Game -- Press 1 2 3 4") myfont = pygame.font.Font(None…

Pizza Pie Charts 是一个基于 Adobe 的 Snap SVG 框架的响应式饼图插件.它着重于集成 HTML 标记和 CSS,而不是 JavaScript 对象,当然Pizza Pie Charts 也支持 JavaScript 对象. 基于 SVG 的图形显示让饼图在视网膜屏幕或任何高清屏幕的设备都很美观.另外,Pizza Pie Charts 能够自适应宽高,或者根据给出的最大宽度或最大高度显示. 您可能感兴趣的相关文章 10款唯美浪漫的婚礼 & 结婚纪念网站模板 那些让人惊…

http://poj.org/problem?id=3122 (题目链接) 题意 给出N个pie的半径和F个friend,每个friend得到的pie必须一样,求每个人能得到的pie的最大大小. solution 经典二分答案. 代码 // poj3122 #include<algorithm> #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> #inc…

由于使用了NDK编译的可执行文件在应用中调用,在4.4及之前的版本上一直没出问题. 最近由于要测试在Android L上的运行情况发现,当运行该可执行文件时,报如下错误: error: only position independent executables (PIE) are supported. PIE这个安全机制从4.1引入,但是Android L之前的系统版本并不会去检验可执行文件是否基于PIE编译出的.因此不会报错.但是Android L已经开启验证,如果调用的可执行文件不是基于PI…

Pie 链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=85904#problem/C 题目: Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I have a number N of them, of various tastes and of various sizes.F…

Pie Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 12985   Accepted: 4490   Special Judge Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I have a number N of them, of various tastes and of…

方法:二分. 题目意思:要过生日了,我请大家吃pie,然后人数一共是f+1(我自己).每个人的pie不能是拼接的,而且每个人的面积是一样的,这样就用二分枚举. 范围是0-最大的那块pie. 然后用每一块去除枚举值,加到cnt上,当cnt>=f+1时候找大一点的面积, 否则找小一点的面积 pie的值要取得精确一点 , = = 另外在输出时候要是%f,如果用%lf会WA的. 上代码! #include <stdio.h> #include <math.h> #define pie…

PIC指的是位置无关代码,用于生成位置无关的共享库,所谓位置无关,指的是共享库的代码断是只读的,存放在代码段,多个进程可同时公用这份代码段而不需要拷贝副本.库中的变量(全局变量和静态变量)通过GOT表访问,而库中的函数,通过PLT->GOT->函数位置进行访问.Linux下编译共享库时,必须加上-fPIC参数,否则在链接时会有错误提示(有资料说AMD64的机器才会出现这种错误,但我在Inter的机器上也出现了).这篇资料不错:http://ixuan.org/2015/01/%E5%8A%A8…

function showData(ele,arr1,arr2){ var myChart2 = echarts.init(document.getElementById(ele)); var option2 = { tooltip : { trigger: 'item', formatter: "{a} <br/>{b} : {c} ({d}%)" }, legend: { orient : 'vertical', x : 'left', data:[arr1[0],ar…

floyd,旅游问题每个点都要到,可重复,最后回来,dp http://poj.org/problem?id=3311 Hie with the Pie Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 4013   Accepted: 2132 Description The Pizazz Pizzeria prides itself in delivering pizzas to its customers as fas…