BUYING FEED 时间限制:3000 ms  |  内存限制:65535 KB 难度:4   描述 Farmer John needs to travel to town to pick up K (1 <= K <= 100)pounds of feed. Driving D miles with K pounds of feed in his truck costs D*K cents. The county feed lot has N (1 <= N<= 100) s…

2020: [Usaco2010 Jan]Buying Feed, II Time Limit: 3 Sec  Memory Limit: 64 MBSubmit: 220  Solved: 162[Submit][Status] Description (buying.pas/buying.in/buying.out 128M 1S) Farmer John needs to travel to town to pick up K (1 <= K <= 100) pounds of feed…

Problem F: F BUYING FEED Description Farmer John needs to travel to town to pick up K (1 <= K <= 100)pounds of feed. Driving D miles with K pounds of feed in his truck costs D*K cents. The county feed lot has N (1 <= N <= 100) stores (convenie…

洛谷 P2616 [USACO10JAN]购买饲料II Buying Feed, II https://www.luogu.org/problemnew/show/P2616 题目描述 Farmer John needs to travel to town to pick up K (1 <= K <= 100) pounds of feed. Driving D miles with K pounds of feed in his truck costs D*K cents. The cou…

洛谷 P2616 [USACO10JAN]购买饲料II Buying Feed, II 洛谷传送门 JDOJ 2671: USACO 2010 Jan Silver 2.Buying Feed, II JDOJ传送门 Description Farmer John needs to travel to town to pick up K (1 <= K <= 100) The county feed lot has N (1 <= N <= 100) stores (conveni…

P2616 [USACO10JAN]购买饲料II Buying Feed, II 题目描述 Farmer John needs to travel to town to pick up K (1 <= K <= 100) pounds of feed. Driving D miles with K pounds of feed in his truck costs D*K cents. The county feed lot has N (1 <= N <= 100) stores…

#include<iostream> #include<cstdio> #include<algorithm> #include<cstring> using namespace std; #define N 352 /* 重量*单价+重量*距离 = 重量*(距离+单价) 预处理单价 贪心:优先买价格低的 */ struct Node { int p;// p = (单价+距离) int w; }c[N]; bool cmp(Node a, Node b)…

http://www.lydsy.com/JudgeOnline/problem.php?id=2020 和背包差不多 同样滚动数组 f[j]表示当前位置j份食物的最小价值 f[j]=min(f[j-l]+l*c) 1<=l<=f 而且在每一步走的时候 f[j]+=j 然后就行了.. #include <cstdio> #include <cstring> #include <cmath> #include <string> #include &…

约翰开车回家,又准备顺路买点饲料了(咦?为啥要说"又"字?)回家的路程一共有 E 公里,这一路上会经过 K 家商店,第 i 家店里有 Fi 吨饲料,售价为每吨 Ci 元.约翰打算买 N 吨饲料,他知道商家的库存是足够的,至少所有店的库存总和不会少于 N.除了购买饲料要钱,运送饲料也是要花油钱的,约翰的卡车上如果装着 X 吨饲料,那么他行驶一公里会花掉 X 2 元,行驶 D 公里需要D X 2 元.已知第 i 家店距约翰所在的起点有 Xi 公里,那么约翰在哪些商店买饲料运回家,才能做到最…

题面 约翰开车来到镇上,他要带V吨饲料回家.如果他的车上有X吨饲料,每公里就要花费X^2元,开车D公里就需要D* X^2元.约翰可以从N家商店购买饲料,所有商店都在一个坐标轴上,第i家店的位置是Xi,饲料的售价为每吨Ci元,库存为Fi.n≤500,k≤10000. 输入格式 第1行:三个整数 V,E,N 第2..N+12..N+1行:第i+1行的三个整数代表Xi​,Fi​,Ci​ . 输出格式 一个整数,代表最小花费. 数据范围 1 ≤ V≤ 10000 , 1 ≤ E ≤ 500 , 1 ≤…