题目传送门 /* 题意:n个程序员,每个人每行写a[i]个bug,现在写m行,最多出现b个bug,问可能的方案有几个 完全背包:dp[i][j][k] 表示i个人,j行,k个bug dp[0][0][0] = 1 表示不选择人的时候所有的bug的种类犯错误都只有一种 dp[i][j][k] += dp[i%2][j-1][k-a[i]]: 错误示范:dp[i][j][k] += dp[i-1][j-l][k-l*a[i]]; 其实要从上一行的状态推出,即少一行 内存限制,滚动数组使用 详细解释:…

题目传送门 /* 题意:在n^n的海洋里是否有k块陆地 构造算法:按奇偶性来判断,k小于等于所有点数的一半,交叉输出L/S 输出完k个L后,之后全部输出S:) 5 10 的例子可以是这样的: LSLSL SLSLS LSLSL SLSLS SSSSS */ #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <string> usi…

题目传送门 /* 题意:一个字符串分割成k段,每段开头字母不相同 水题:记录每个字母出现的次数,每一次分割把首字母的次数降为0,最后一段直接全部输出 */ #include <cstdio> #include <iostream> #include <cstring> #include <string> #include <algorithm> using namespace std; ; const int INF = 0x3f3f3f3f;…

C. Remembering Strings Time Limit: 20 Sec  Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/543/problem/C Description You have multiset of n strings of the same length, consisting of lowercase English letters. We will say that those strings ar…

D - Destroying Roads Time Limit: 20 Sec  Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/544/problem/D Description In some country there are exactly n cities and m bidirectional roads connecting the cities. Cities are numbered with integers f…

C. Writing Code Time Limit: 20 Sec  Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/544/problem/C Description Programmers working on a large project have just received a task to write exactly m lines of code. There are n programmers working o…

B. Sea and Islands Time Limit: 20 Sec  Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/544/problem/B Description A map of some object is a rectangular field consisting of n rows and n columns. Each cell is initially occupied by the sea but yo…

A. Set of Strings Time Limit: 20 Sec  Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/544/problem/A Description You are given a string q. A sequence of k strings s1, s2, ..., sk is called beautiful, if the concatenation of these strings is st…

链接: http://codeforces.com/contest/543 过程: 惨淡的只做出了A和C 题解: A 题解: 简单的一道题 我们用$dp[i][j]$表示当前考虑到前num个人(这个另外枚举),当前写了$i$行代码,当前的bug数量为$j$的方案数 然后转移就是$dp[i][j]=\sum {dp[i-1][j-a[num]]}$ Code: #include<stdio.h> #include<cstring> #include<cstdlib> #i…

C. Writing Code time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output Programmers working on a large project have just received a task to write exactly m lines of code. There are n programmers w…