Description The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are res…

Reactor Cooling time limit per test: 0.5 sec. memory limit per test: 65536 KB input: standard output: standard The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nu…

The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are responsible for…

题目链接: http://acm.sgu.ru/problem.php?contest=0&problem=194 题目大意: n个点(n<20000!!!不是200!!!RE了无数次),m条边(管子)(m范围好像没说,我开了10^6),每个点流入的和流出的液体要相等,每条边(管子)有上下界流量,问是否有解,有解YES无解NO,有解还要输出每条边的流量. 题目输入样例略坑,我以为要多组数据输入输出TEST #1 什么的.后来仔细看了Input发现只有一组吧应该,保险起见还是写了多组,但是不用…

http://acm.sgu.ru/problem.php?contest=0&problem=194 题意:m条有向边,有上下界,求最大流. 思路:原图中有u-v low[i],high[i] 建图就是u->v,high[i]-low[i],同时du[u]-=low[i],du[v]+=low[i],然后对于每个点i,如果du[i]>0,那就S->i,du[i],若是du[i]<0那就i->T ,-du[i],然后判断S出去的流是不是满流,不是就无解,否则每条边流量…

[题目链接] http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=20757 [题意] 求有容量上下界的无源无汇可行流. [思路] 无源无汇可行流要求所有的顶点都满足流量平衡. 基本思路是转化成最大流来做. 对于边(u,v,b,c),连边(u,v,c-b).为了保持流量平衡,我们还需要连边         1.(S,u,inB[u]-outB[u])  inB>outB 2.(u,T,outB[u]-inB[u])  outB>…

题目链接 题意:有向图中有n(1 <= n <= 200)个点,无自环或者环的节点个数至少为3.给定每条边的最小流量和最大流量,问每条边的可行流量为多少? 思路:一般求解的网络流并不考虑下界问题,即流量可以为0,在有下界时,我们只需将上界变成r-l,这时还需要满足流量守恒,增加源点s和汇点t,当点u的流入大于流出时,将点u与s连边,容量即为多出的流量.同理当u流出大于流入时,多出来的流出的流量连到汇点t;直接跑最大流:这时得到的只是网络中的可行流: 为什么处理完下界之后是这样与超级源点和汇点连…

时间限制:0.5s 空间限制:6M 题意: 显然就是求一个无源汇有上下界的网络流的可行流的问题 Solution: 没什么好说的,直接判定可行流,输出就好了 code /* 无汇源有上下界的网络流 */ #include <iostream> #include <cstring> #define ms(a,b) memset(a,b,sizeof a) using namespace std; ; struct node { int u, v, c, ne; } edge[MAXN…

[题目分析] 无源汇上下界可行流. 上下界网络流的问题可以参考这里.↓ http://www.cnblogs.com/kane0526/archive/2013/04/05/3001108.html [代码] #include <cstdio> #include <cstring> #include <cmath> #include <cstdlib> //#include <map> #include <set> #include…

题意:给定上一个有容量和下界的网络,让你求出一组可行解. 析:先建立一个超级源点 s 和汇点 t ,然后在输入时记录到每个结点的下界的和,建边的时候就建立c - b的最后再建立 s 和 t , 在建立时,如果 i 结点的输入的大于输出的,那么就是从 s 建立一条边,否则 i 与 t 建立,然后跑一次最大流,就OK了,注意求出的流量是没有下界,再加上下界的就好了. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000")…

题意: 给定n个点和m条边, 每条边有流量上下限[b,c], 求是否存在一种流动方法使得每条边流量在范围内, 而且每个点的流入 = 流出 分析: 无源汇有上下界最大流模板, 记录每个点流的 in 和 out , 然后如果一个点 i 的in > out,  从源点i连一条边到in, out > in 就从i 连一条边到 v. #include <cstdio> #include <iostream> #include <cstring> #include &l…

194. Reactor Cooling time limit per test: 0.5 sec. memory limit per test: 65536 KB input: standard output: standard The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for t…

Reactor Cooling Time Limit: 5 Seconds      Memory Limit: 32768 KB      Special Judge The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planni…

Reactor Cooling 无源汇上下界最大流问题. 1.流量平衡. 2.满足上下界 模板题. #include <iostream> #include <queue> #include <vector> #include <cstdio> #include <cstring> using namespace std; const int MAXN = 200000 + 10; const int INF = 1 << 30; s…

称号:acdream 1211 Reactor Cooling 分类:无汇的有上下界网络流. 题意: 给n个点.及m根pipe,每根pipe用来流躺液体的.单向的.每时每刻每根pipe流进来的物质要等于流出去的物质,要使得m条pipe组成一个循环体.里面流躺物质. 而且满足每根pipe一定的流量限制,范围为[Li,Ri].即要满足每时刻流进来的不能超过Ri(最大流问题).同一时候最小不能低于Li. 比如: 个pipe) ,下界为1) 23 1 3 3 4 1 3 4 1 1 3 1 3 1 3…

 Description The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are re…

ZOJ 1314 Reactor Cooling | 上下界无源汇可行流 题意 有一个网络,每条边有流量的上界和下界,求一种方案,让里面的流可以循环往复地流动起来. 题解 上下界无源汇可行流的模型: 设置虚拟源点和虚拟汇点. 如果一条边\(u \to v\)的下界是\(mi\).上界是\(ma\),则在图中建一条\(u \to v\)的边,流量是\(ma - mi\),同时记录\(oud[u] += mi, ind[v] += mi\),分别代表\(u\)实际比图上多流出的流量与\(v\)实际比…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2314 The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create.…

Reactor Coolinghttp://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1314 Time Limit: 5 Seconds      Memory Limit: 32768 KB      Special Judge The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear re…

题目描述 The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are responsibl…

Reactor Cooling The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are…

The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are responsible for…

Reactor Cooling Time Limit: 5000ms Memory Limit: 32768KB This problem will be judged on ZJU. Original ID: 231464-bit integer IO format: %lld      Java class name: Main Special Judge   The terrorist group leaded by a well known international terrorist…

The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Being the wicked computer genius of this group, you are responsible for…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1314 The terrorist group leaded by a well known international terrorist Ben Bladen is buliding a nuclear reactor to produce plutonium for the nuclear bomb they are planning to create. Be…

sgu194:http://acm.sgu.ru/problem.php?contest=0&problem=194 题意:题目大意:给n个点,及m根pipe,每根pipe用来流躺液体的,单向的,每时每刻每根pipe流进来的物质要等于流出去的物质,要使得m条pipe组成一个循环体,里面流躺物质.并且满足每根pipe一定的流量限制,范围为[Li,Ri].即要满足每时刻流进来的不能超过Ri(最大流问题),同时最小不能低于Li. 题解:题解:.对于每根管子有一个上界容量up和一个下界容量low,我们让…

/* 题意:无源无汇,并且每条边的容量有上下界限的网络流问题!既然无源无汇,那么素有的节点都应该满足“入流==出流”! 输出每一条边的流量,使得满足上面的条件.(如果u->v有流量,那么v->u就不会有流量) 思路:如果增加了源点s和汇点t,对于u->v(下限为l, 上限为f) 将这一条边拆成3条,s->v(容量为l), u->v(容量为f-l) u->t(容量为l)这样就变成了每一个点的流入或者流出的流量至少是b!然后从s->t走一遍最大流,如果所有的附件边都已…

题目大概说一个核反应堆的冷却系统有n个结点,有m条单向的管子连接它们,管子内流量有上下界的要求,问能否使液体在整个系统中循环流动. 本质上就是求一个无源汇流量有上下界的容量网络的可行流,因为无源汇的容量网络上各个顶点都满足流量平衡条件,即所有点的∑流入流量=∑流出流量,可以看成里面的流是循环流动的,类似有向图欧拉回路. 而带上下界的网络可行流的求法,是根据网络流中一个流是可行流的充分必要条件——限制条件和平衡条件,去改造原网络,转化成不带下界的容量网络来求解的.数学模型那些证明之类的不难理解,见…

题意: 给点数n和边数m. 接下来m条有向边. a b c d 一次代表起点终点,下界上界. 求: 判断是否存在可行流,若存在则输出某可行流.否则输出IMPOSSIBLE 思路: <一种简易的方法求解流量有上下界的网络中的网络流问题> #include<stdio.h> #include<string.h> #include<algorithm> #include<string.h> #include<vector> #define…

模板类型的题详细參考国家集训队论文:http://wenku.baidu.com/view/0f3b691c59eef8c75fbfb35c.html 參考博客:http://blog.csdn.net/qq172108805/article/details/7783010 #include<stdio.h> #include<string.h> #include<queue> using namespace std; #define N 300 #define inf…