1043 Is It a Binary Search Tree(25 分) A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a nod…

题目 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys gre…

#include <cstdio> #include <climits> #include <cstdlib> #include <vector> const double LO_BOUND = -1.0 + INT_MIN; const double HI_BOUND = +1.0 + INT_MAX; using namespace std; class Node { public: Node* L; Node* R; int data; Node(,…

1043 Is It a Binary Search Tree(25 分) A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a nod…

1043 Is It a Binary Search Tree (25 分)   A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a…

PAT甲级:1064 Complete Binary Search Tree (30分) 题干 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtre…

https://pintia.cn/problem-sets/994805342720868352/problems/994805440976633856 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than th…

题目 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The lef subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys grea…

1064. Complete Binary Search Tree (30) 时间限制 100 ms 内存限制 32000 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only…

A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys greate…

https://pintia.cn/problem-sets/994805342720868352/problems/994805367987355648 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than th…

本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90701125 1099 Build A Binary Search Tree (30 分)   A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node cont…

1099. Build A Binary Search Tree (30) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only…

A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys greate…

题目 A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys gre…

A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys greate…

Two elements of a binary search tree (BST) are swapped by mistake. Recover the tree without changing its structure. Note:A solution using O(n) space is pretty straight forward. Could you devise a constant space solution? 给定一个排序二叉树,然后任意交换了其中两个节点,要求在使用…

Given a binary tree, determine if it is a valid binary search tree (BST). Assume a BST is defined as follows: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys…

二叉查找树简介 二叉查找树(Binary Search Tree), 也成二叉搜索树.有序二叉树(ordered binary tree).排序二叉树(sorted binary tree), 是指一棵空树或者具有下列性质的的二叉树: 1. 若任意节点的左子树不空,在左子树上所有结点的值均小于或等于它的根结点的值: 2. 任意节点的右子树不空,则右子树上所有结点的值均大于它的根结点的值: 3. 任意节点的左子树.右子树也分别为二叉查找树. 4. 没有键值相等的结点(no duplicate no…

简单题.构造出二叉搜索树,然后check一下. #include<stdio.h> #include<algorithm> using namespace std; +; struct Node { int left; int right; int val; } s[maxn]; int n; int a[maxn]; int ans[maxn],tot; int h[maxn]; int k; void dfs(int x) { ans[k++]=s[x].val; ) dfs(…

博主欢迎转载,但请给出本文链接,我尊重你,你尊重我,谢谢~http://www.cnblogs.com/chenxiwenruo/p/6789220.html特别不喜欢那些随便转载别人的原创文章又不给出链接的所以不准偷偷复制博主的博客噢~~ 题意:给出一个序列,问你是否是一棵二叉搜索树或者是其镜像的前序遍历.并且输出其后序遍历. 一开始没考虑到只有一个子树...比如BST78 11 9 8 10 13 12MIRROR78 11 13 12 9 10 8所以要先判断是否为BST,不是的话再判断是…

题意: 输入一个正整数N(<=1000),接下来输入N个点的序号.如果刚才输入的序列是一颗二叉搜索树或它的镜像(中心翻转180°)的先序遍历,那么输出YES并输出它的后序遍历,否则输出NO. trick: for(auto it:post) cout<<it<<((it!=post[n-1])?" ":""); 这样输出会使第0,1数据点格式错误...原因未知 cout<<post[0]; for(int i=1;i<…

the problem is from pat,which website is http://pat.zju.edu.cn/contests/pat-a-practise/1043 and the source code is as followed. #include<iostream> #include<vector> #include<cstdio> using namespace std; int pos; struct cell { cell *lchild…

http://www.patest.cn/contests/pat-a-practise/1043 #include <stdio.h> #include <vector> using namespace std; struct Node { Node* lchild; Node* rchild; int val; }Tree[]; int loc,loc2,loc3; Node* create() { Tree[loc].lchild=NULL; Tree[loc].rchild…

#include<bits/stdc++.h> using namespace std; typedef struct node; typedef node *tree; struct node { int data; tree L,R; }; void Insert(tree &bt,int x) { if(bt==NULL){ bt=new node; bt->data=x; bt->L=NULL; bt->R=NULL; return; } if(x<bt…

题意:输入一个正整数N(<=1000),接着输入N个非负整数(<=2000),输出完全二叉树的层次遍历. AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; ]; ]; int cnt; int n; void dfs(int x){ if(x>n) return; dfs(x*); tree[x]=a[++cnt]; dfs(x*+); }…

因为是要构造完全二叉树,所以树的形状已经确定了. 因此只要递归确定每个节点是多少即可. #include<cstdio> #include<cstring> #include<cmath> #include<queue> #include<vector> #include<string> #include<stack> #include<map> #include<algorithm> using…

Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST.   和上一题类似,把数组换成链表,所以可以两种做法: 1.把链表换成数组,然后用上一题的方法,这样会比较慢. 2.每次找到中间的点,作为节点,然后递归,其实原理还是二分查找.   /** * Definition for singly-linked list. * public…

Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 给一个排好序的数组,然后求搜索二叉树 其实就是二分法,不难. /** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNo…

public TreeNode sortedListToBST(ListNode head) { if(head==null) return new TreeNode(0); ArrayList<TreeNode> arr=new ArrayList<TreeNode>(); while(head!=null) { arr.add(new TreeNode(head.val)); head=head.next; } return BST(arr,0,arr.size()-1); }…