Given an array A of integers, for each integer A[i] we may choose any x with -K <= x <= K, and add x to A[i]. After this process, we have some array B. Return the smallest possible difference between the maximum value of B and the minimum value of B…

题目要求 Given an array A of integers, for each integer A[i] we may choose any x with -K <= x <= K, and add x to A[i]. After this process, we have some array B. Return the smallest possible difference between the maximum value of B and the minimum value…

problem 908. Smallest Range I solution: class Solution { public: int smallestRangeI(vector<int>& A, int K) { ], mn = A[]; for(auto a:A) { mx = max(mx, a); mn = min(mn, a); } , mx-mn-*K); } }; 参考 1. Leetcode_easy_908. Smallest Range I; 2. discuss…

Given an array A of integers, for each integer A[i] we need to choose either x = -K or x = K, and add x to A[i] (only once). After this process, we have some array B. Return the smallest possible difference between the maximum value of B and the mini…

You have k lists of sorted integers in ascending order. Find the smallest range that includes at least one number from each of the k lists. We define the range [a,b] is smaller than range [c,d] if b-a < d-c or a < c if b-a == d-c. Example 1: Input:[…

You have k lists of sorted integers in ascending order. Find the smallest range that includes at least one number from each of the k lists. We define the range [a,b] is smaller than range [c,d] if b-a < d-c or a < c if b-a == d-c. Example 1: Input:[…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 数学计算 日期 题目地址:https://leetcode.com/problems/smallest-range-i/description/ 题目描述 Given an array A of integers, for each integer A[i] we may choose any x with -K <= x <= K, and ad…

Given an array A of integers, for each integer A[i] we may choose any x with -K <= x <= K, and add xto A[i]. After this process, we have some array B. Return the smallest possible difference between the maximum value of B and the minimum value of B.…

题目如下: 解题思路:简单的不能再简单的题目了,对于任意一个A[i]来说,其可能的最小的最大值是A[i]-K,最大的最小值是A[i]+K.遍历数组,求出所有元素中最大的最小值和最小的最大值,两者之差(小于零则取零)就是答案. 代码如下: class Solution(object): def smallestRangeI(self, A, K): """ :type A: List[int] :type K: int :rtype: int """…

题目 : Given an array A of integers, for each integer A[i] we may choose any x with -K <= x <= K, and add x to A[i]. After this process, we have some array B. Return the smallest possible difference between the maximum value of B and the minimum value…