Give you a string with length N, you can generate N strings by left shifts. For example let consider the string “SKYLONG”, we can generate seven strings:String Rank SKYLONG 1KYLONGS 2YLONGSK 3LONGSKY 4ONGSKYL 5NGSKYLO 6GSKYLON 7and lexicographically…

Give you a string with length N, you can generate N strings by left shifts. For example let consider the string “SKYLONG”, we can generate seven strings: String Rank SKYLONG 1 KYLONGS 2 YLONGSK 3 LONGSKY 4 ONGSKYL 5 NGSKYLO 6 GSKYLON 7 and lexicograp…

String Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1492    Accepted Submission(s): 662 Problem Description Give you a string with length N, you can generate N strings by left shifts.…

KMP,在有循环节的前提下: 循环节 t = len-next[len], 个数num = len/(len-next[len]);个人理解,如果有循环节,循环节长度必定小于等于len/2, 换句话说next[len]>=len/2;对于len%(len-next)!=0的这种情况不讨论,循环节不存在.下面是假设循环节存在的情况当次数等于2, 对于abcabc这种情况就不用说了,len = 6, next[len] = 3;当次数大于2,对于串a1 a2 a3 a4 a5 a6 a7 a8 a9…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3374 题目大意:给出一个字符串,依次左移一个单位形成一堆字符串,求其字典序最小和最大的字符串需要左移多少位,以及一共有几个这样的字符串(例如0101->1010->0101). 解题思路:首先可以确定两个字符串出现的次数应该相同,即循环节数目,这个比较容易得到.然后就是最大最小字符串如何得到的问题了,直接暴力肯定超时.... 所以这里找到了比较好的方法,转载:http://blog.csdn.ne…

题目链接:https://vjudge.net/problem/HDU-3374 String Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3646    Accepted Submission(s): 1507 Problem Description Give you a string with length N,…

bzoj5130 字符串的周期(kmp,最小表示法) bzoj 题解时间 m很大,n很小. 周期很容易求,就是kmp之后n-fail[n]. 之后对于枚举所有的字符串用最小表示法,暴力搜索. 能过就完事了. #include<bits/stdc++.h> using namespace std; typedef long long lint; struct pat{int x,y;pat(int x=0,int y=0):x(x),y(y){}bool operator<(const p…

Problem Description Give you a string with length N, you can generate N strings by left shifts. For example let consider the string “SKYLONG”, we can generate seven strings:String Rank SKYLONG 1KYLONGS 2YLONGSK 3LONGSKY 4ONGSKYL 5NGSKYLO 6GSKYLON 7an…

String Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4828    Accepted Submission(s): 1949 Problem Description Give you a string with length N, you can generate N strings by left shifts…

地址:http://acm.hdu.edu.cn/showproblem.php?pid=3374 题目: String Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3029    Accepted Submission(s): 1230 Problem Description Give you a string wi…