Divide the Sequence 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5783 Description Alice has a sequence A, She wants to split A into as much as possible continuous subsequences, satisfying that for each subsequence, every its prefix sum is not smal…

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Divide the Sequence 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5783 Description Alice has a sequence A, She wants to split A into as much as possible continuous subsequences, satisfying that for each subsequence, every its prefix sum is not smal…

Divide the Sequence Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 649    Accepted Submission(s): 331 Problem Description Alice has a sequence A, She wants to split A into as much as possible c…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5783 题目大意: 把一个N个数的数列拆成若干段,保证每一段的前缀和都非负,求最多能拆成多少段. 题目思路: [贪心] 一开始题目看错了看成每一段内和非负..DPWA了好久. 默认答案是n,从后往前找负数,找到一个负数就一直把它往前合并直到和值非负,这样这个区间的前缀和就一定非负,扣除合并的区间大小即可. // //by coolxxx //#include<bits/stdc++.h> #inc…

Description Alice has a sequence A, She wants to split A into as much as possible continuous subsequences, satisfying that for each subsequence, every its prefix sum is not small than 0. Input The input consists of multiple test cases. Each test case…

题意:求将一串数据尽可能多分成所有前缀和大于0的连续子串. 思路:由于是要求所有前缀和大于0,那么只要从后往前推就好了. #include<bits/stdc++.h> using namespace std; ; long long arr[maxn], n; int main(){ while(~scanf("%d", &n)){ ; i < n; i ++) scanf("%lld", &arr[i]); ; ; ; i &g…

Divide the Sequence 题意: 给你一个序列A,问你最多能够分成多少个连续子序列,使得每个子序列的所有前缀和均不小于0 题解: 这题是比赛时候的水题,但我比的时候也就做出这一题, = = 首先我想的是把他们前缀和求出来,之后试了下样例,一点鸟用都没有,那正着不行就倒着试下呗,之后发现这样有用,我先想到的思路是求后缀和,只要>=0就ans++,但那时队友举出了反例,比如2 1 -3 3的时候应该是2,我的算法就是4,那接着马上就能想到如果后缀和大于0,那么就要把他赋为0,之后举了几…

// 判断相同区间(lazy) 多校8 HDU 5828 Rikka with Sequence // 题意:三种操作,1增加值,2开根,3求和 // 思路:这题与HDU 4027 和HDU 5634 差不多 // 注意开根号的话,遇到极差等于1的,开根号以后有可能还是差1.如 // 2 3 2 3... // 8 9 8 9... // 2 3 2 3... // 8 9 8 9... // 剩下就是遇到区间相等的话,就直接开根号不往下传 #include <bits/stdc++.h> u…

HDU5014Number Sequence(贪心) 题目链接 题目大意: 给出n,然后给出一个数字串,长度为n + 1, 范围在[0, n - 1].然后要求你找出另外一个序列B,满足上述的要求,而且使得t = A0^B0 + Ai + 1 ^ Bi + 1 + ... + An ^ Bn 最大. 解题思路: 对于一个数字进行异或,要求结果最大的话,那么取这个数字的二进制互补数字是最好的情况,而且能够发现每次找到一个数字和相应的互补的数字都会是一段区间.就这样一段一段区间的去寻找每一个点相应的…

题目链接:hdu 4983 Wow! Such Sequence! 题目大意:就是三种操作 1 k d, 改动k的为值添加d 2 l r, 查询l到r的区间和 3 l r. 间l到r区间上的所以数变成近期的斐波那契数,相等的话取向下取. 解题思路:线段树.对于每一个节点新增一个bool表示该节点下面的位置是否都是斐波那契数. #include <cstdio> #include <cstring> #include <cstdlib> #include <algo…

hdu 4825 Xor Sum(trie+贪心) 刚刚补了前天的CF的D题再做这题感觉轻松了许多.简直一个模子啊...跑树上异或x最大值.贪心地让某位的值与x对应位的值不同即可. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #define CLR(a,b) memset((a),(b),sizeof(…

[题解]Cut the Sequence(贪心区间覆盖) POJ - 3017 题意: 给定一大堆线段,问用这些线段覆盖一个连续区间1-x的最小使用线段的数量. 题解 考虑一个这样的贪心: 先按照左端点排序,若左端点一样则谁长谁在前.现在判无解就方便了,记录一下前缀max即可.然后现在要最小化选择. 记录一个最右端点\(R\),一个暴力的办法是暴力循环判断所有线段是否满足条件,这样显然超时,你决定优化一下常数,所以你记录一下从哪个线段开始才\(l_i \ge R\).你以为你是常数优化,其实你复…

题目链接: Hdu 5496 Beauty of Sequence 题目描述: 一个整数序列,除去连续的相同数字(保留一个)后,序列的和成为完美序列和.问:一个整数序列的所有子序列的完美序列和? 解题思路: 考虑位于i位置数字x的贡献值,假设x是子序列中连续相同数字的第一个,那么x对于i后面的数有2(n-i)个贡献值,对前面的数,要么不选取,要么选取结尾不为x的方案数目. #include <map> #include <cstdio> #include <cstring&g…

Hdu 5806 NanoApe Loves Sequence Ⅱ(双指针) Hdu 5806 题意:给出一个数组,求区间第k大的数大于等于m的区间个数 #include<queue> #include<cmath> #include<cstdio> #include<cstring> #include<cstdlib> #include<iostream> #include<algorithm> #define ll l…

HDU 5063 Operation the Sequence 题目链接 把操作存下来.因为仅仅有50个操作,所以每次把操作逆回去执行一遍,就能求出在原来的数列中的位置.输出就可以 代码: #include <cstdio> #include <cstring> #include <algorithm> using namespace std; typedef long long ll; const int N = 100005; const ll MOD = 1000…

 HDU 5288 OO’s Sequence http://acm.hdu.edu.cn/showproblem.php?pid=5288 OO has got a array A of size n ,defined a function f(l,r) represent the number of i (l<=i<=r) , that there’s no j(l<=j<=r,j<>i) satisfy a i mod a j=0,now OO want to k…

HDU - 1711 A - Number Sequence   Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... ,…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5783 题意:给n个数,要求划分成多个段,使得每一个段的任意前缀和都不小于0. 从后往前截取,这样不会影响到未截取的部分.维护当前的前缀和,每次截取不要忘记给前缀和置零. #include <bits/stdc++.h> using namespace std; typedef long long LL; ; int n, ret; LL cur; LL a[maxn]; int main() {…

Description Steph is extremely obsessed with “sequence problems” that are usually seen on magazines: Given the sequence 11, 23, 30, 35, what is the next number? Steph always finds them too easy for such a genius like himself until one day Klay comes…

题目网址:http://acm.hdu.edu.cn/showproblem.php?pid=6047 题目: Maximum Sequence Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 90    Accepted Submission(s): 44 Problem Description Steph is extremely o…

题意:给定一个序列,让你构造出一个序列,满足条件,且最大.条件是 选取一个ai <= max{a[b[j], j]-j} 析:贪心,贪心策略就是先尽量产生大的,所以就是对于B序列尽量从头开始,由于数据比较大,采用桶排序,然后维护一个单调队列,使得最头上最大. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #i…

题目:给出N个只有左右括号字符串 ,这N个字符串的排列顺序是任意的 , 问按最优的排序后 , 得到最多匹配的括号个数 分析: 我们很容易的想到 字符串)()()(( , 这样的字符串可以精简为)(( 因为无论如何的排序 ,对于字符串可以匹配的括号是不会变的 : 那么问题就可以简化为对与 **)(**    )     (   这几种类型的字符串的排序情况 : 我们也很自然而然的想到了贪心 ,那问题来了 ,我们该如何贪心呢?先从小问题出发 , 有A 与 B两串 , 在自然的可以想到 排序的情况肯定…

题目大意:给一个整数序列,将其划分成若干个子连续序列,使其每个子序列的前缀和不为负.求最大的划分个数. 题目分析:从后往做累加计算,如果不为负,则计数加一,累加和清0.否则,一直往前扫描.如果最终的和为负,答案为0,否则为计数结果. 代码如下: # include<iostream> # include<cstdio> # include<algorithm> using namespace std; # define LL long long const int N=…

hdu4915 Parenthese sequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 82    Accepted Submission(s): 25 Problem Description bobo found an ancient string. The string contains only three c…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5273 Dylans loves sequence Description Dylans is given $N$ numbers $a[1]....a[N]$ And there are $Q$ questions. Each question is like this $(L,R)$ his goal is to find the “inversions” from number $L$ to n…

Dylans loves sequence Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5273 Description Dylans得到了N个数a[1]...a[N].有Q个问题,每个问题形如(L,R)他需要求出L−R这些数中的逆序对个数.更加正式地,他需要求出二元组(x,y)的个数,使得L≤x,y≤R且x<y且a[x]>a[y] Input 第一行有两个数N和Q…

NanoApe Loves Sequence Ⅱ 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5806 Description NanoApe, the Retired Dog, has returned back to prepare for for the National Higher Education Entrance Examination! In math class, NanoApe picked up sequences on…

NanoApe Loves Sequence 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5805 Description NanoApe, the Retired Dog, has returned back to prepare for the National Higher Education Entrance Examination! In math class, NanoApe picked up sequences once aga…

Wow! Such Sequence! 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=4893 Description Recently, Doge got a funny birthday present from his new friend, Protein Tiger from St. Beeze College. No, not cactuses. It's a mysterious blackbox. After some resea…