// 题意 : 一个人要去旅行 给你起点和终点 求最少花费 其中花费为经过路径的总费用减去该路径的中的最大花费段// 直接搜索 稍微加了个剪枝 主要是数据规模小#include <iostream> #include <map> #include <algorithm> #include <queue> #include <math.h> #include <stdio.h> #include <string.h> #in…

题目链接: http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2027 题目: Samball is going to travel in the coming vacation. Now it's time to make a plan. After choosing the destination city, the next step is to determine the travel route. As this…

给一张有向无环图,边都有花费,从某点到某点走的那条路径上的那一条花费最多的边可以省掉,问从起点到终点的最少花费的多少, 往DP想的话,就可以写出这个状态dp[u][mx],表示到达u点已经省掉的花费为mx的最少花费. 用SPFA更新转移方程..或者理解成队列+我为人人的转移..其实这题这样子也能解有环图. 看了别人博客,发现还有三种解法: 枚举每一条边作为省掉的边,n次SPFA.这方法简洁,可惜想不出= = 跑Dijkstra,根据记录到每一点时的最长边更新,正确性不懂.. Floyd+DP:加…

POJ 1511 Invitation Cards / UVA 721 Invitation Cards / SPOJ Invitation / UVAlive Invitation Cards / SCU 1132 Invitation Cards / ZOJ 2008 Invitation Cards / HDU 1535 (图论,最短路径) Description In the age of television, not many people attend theater perfor…

Travelling Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2554    Accepted Submission(s): 746 Problem DescriptionAfter coding so many days,Mr Acmer wants to have a good rest.So travelling is th…

ZOJ题目分类初学者题: 1001 1037 1048 1049 1051 1067 1115 1151 1201 1205 1216 1240 1241 1242 1251 1292 1331 1334 1337 1338 1350 1365 1382 1383 1394 1402 1405 1414 1494 1514 1622 1715 1730 1755 1760 1763 1796 1813 1879 1889 1904 1915 1949 2001 2022 2099 2104 21…

http://acm.hdu.edu.cn/showproblem.php?pid=3001 从任何一个点出发,去到达所有的点,但每个点只能到达2次,使用的经费最小.三进制 Travelling Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3541    Accepted Submission(s): 1106 Problem Des…

Travelling Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3905    Accepted Submission(s): 1234 Problem Description After coding so many days,Mr Acmer wants to have a good rest.So travelling is…

Travelling Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6600    Accepted Submission(s): 2144 Problem Description After coding so many days,Mr Acmer wants to have a good rest.So travelling is…

题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=3001 Travelling Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 5295    Accepted Submission(s): 1718 Problem Description After coding so many days,…