LeetCode: Interval】的更多相关文章

(1)Merge Intervals https://leetcode.com/problems/merge-intervals/ Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. 思路:贪心思想.首先根据intervals的start进行排序.排完序之后,先将第一个i…
Given a set of intervals, for each of the interval i, check if there exists an interval j whose start point is bigger than or equal to the end point of the interval i, which can be called that j is on the "right" of i. For any interval i, you ne…
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9], insert and merge…
Given a set of intervals, for each of the interval i, check if there exists an interval j whose start point is bigger than or equal to the end point of the interval i, which can be called that j is on the "right" of i. For any interval i, you ne…
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9], insert and merge…
题目来源 https://leetcode.com/problems/insert-interval/ Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Examp…
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […
作者:jostree  转载请注明出处 http://www.cnblogs.com/jostree/p/4051169.html 题目链接:leetcode Insert Interval 使用模拟的方法,把需要插入的区间和每一个给定的区间进行比较,有三种情况: 1.给定区间的起点小于要插入区间的终点,并且区间还未被查入过,那么插入区间. 2.给定区间的终点大于要插入区间的起点,或者插入区间已经被插入过了,那么插入给定区间. 3.不满足以上两种情况,说明给定区间与插入区间有交集,那么把需要插入…
  Given a set of intervals, for each of the interval i, check if there exists an interval j whose start point is bigger than or equal to the end point of the interval i, which can be called that j is on the "right" of i. For any interval i, you…
一天一道LeetCode系列 (一)题目 Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,…
原题地址:https://oj.leetcode.com/problems/insert-interval/ 题意: Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times…
1. 原题链接 https://leetcode.com/problems/insert-interval/description/ 2. 题目要求 该题与上一题的区别在于,插入一个新的interval对象,将此对象与所给列表里的Interval对象进行合并. 3. 解题思路 首先遍历Interval对象列表,找到插入位置.将插入位置之前的列表中的Interval对象直接加入结果列表. 然后查找所要插入Interval对象的end属性在列表中的位置. 最后将列表中剩余的Interval对象全部加…
Interval的合并时比较常见的一类题目,网上的Amazon面经上也有面试这道题的记录.这里以LeetCode上的例题做练习. Merge Intervals Given a collection of intervals, merge all overlapping intervals. For example,Given [1,3],[2,6],[8,10],[15,18],return [1,6],[8,10],[15,18]. /** * Definition for an inter…
https://oj.leetcode.com/problems/insert-interval/ 给出有序的区间来,再插入进去一个,也就是区间合并. 刚开始确立了几个思路,看要插入的区间的start和end分别位于什么位置.区分是在空闲处还是在一个区间里面,并且还要判断跨越了几个区间,并且要进行数组元素的后移之类的.写了代码比较麻烦,于是想新的思路.如下:新建立一个数组,这样从前往后扫描老数组和要插入元素的关系,如果还没到插入元素,则正常将老数组元素复制到新数组里面,如果到了要插入的元素,则开…
题目 Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Given intervals [1,3],[6,9], insert and mer…
Given a set of intervals, for each of the interval i, check if there exists an interval j whose start point is bigger than or equal to the end point of the interval i, which can be called that j is on the "right" of i. For any interval i, you ne…
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Input: intervals = [[1,3],[6,9]], newInterval…
题目: Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1: Input: intervals = [[1,3],[6,9]], newInter…
LeetCode中,有很多关于一组interval的问题.大体可分为两类: 1.查看是否有区间重叠: 2.合并重叠区间;  3.插入新的区间: 4. 基于interval的其他问题 [ 做题通用的关键步骤]: 1. 按照begin时间排序: 2. 判断两个相邻区间是否重叠: [假设] a. 给定的区间是半开区间 [begin, end); b. 已经按照"begin"排序. c. 当前的区间是begin, end; 要比较/合并的区间:[ intervals[i][0], interv…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 双指针 日期 题目地址:https://leetcode.com/problems/interval-list-intersections/ 题目描述 Given two lists of closed intervals, each list of intervals is pairwise disjoint and in sorted order…
[LeetCode]436. Find Right Interval 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/find-right-interval/description/ 题目描述: Given a set of intervals, for each of the interval i,…
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […
Given a set of intervals, for each of the interval i, check if there exists an interval j whose start point is bigger than or equal to the end point of the interval i, which can be called that j is on the "right" of i. For any interval i, you ne…
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […
Insert Interval Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], in…
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […
原题地址 遍历每个区间intervals[i]: 如果intervals[i]在newInterval的左边,且没有交集,把intervals[i]插入result 如果intervals[i]在newInterval的右边,且没有交集,如果newInterval还没插入,则将newInterval插入result,之后再插入intervals[i] 如果intervals[i]和newInterval有交集,则更新newInterval的start.end 代码: vector<Interva…
刚开始做这个题的时候绕了好大的圈,对问题的分析不全面,没能考虑所有情况,做的很纠结.后来看了下大神的做法很受启发,改了改代码,最终提交了. public static ArrayList<Interval> insert(ArrayList<Interval> intervals, Interval newInterval) { ArrayList<Interval> ips=null; ips=new ArrayList<Interval>(); int…
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary). You may assume that the intervals were initially sorted according to their start times. Example 1:Given intervals [1,3],[6,9], insert and merge […