Have Fun with Numbers (大数)

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PAT 1023 Have Fun with Numbers[大数乘法][一般]

1023 Have Fun with Numbers (20)(20 分) Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exac…

Have Fun with Numbers (大数)

Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactly the numbers from 1 to 9, only in a…

hdu 5585 Numbers【大数+同余定理】

Numbers Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 460 Accepted Submission(s): 283 Problem Description There is a number N.You should output "YES" if N is a multiple of 2, 3 or 5,ot…

ACM学习历程—HDU5585 Numbers（数论 || 大数）(BestCoder Round #64 (div.2) 1001)

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5585 题目大意就是求大数是否能被2,3,5整除. 我直接上了Java大数,不过可以对末尾来判断2和5,对所有位的和来判断3. 代码就不粘了.…

ural 1012. K-based Numbers. Version 2（大数dp）

和1009相同,只是n达到了180位,可以模拟大数加和大数乘,这里用的java中的大数. import java.math.BigInteger; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner cin = new Scanner(System.in); while (cin.hasNext()) { int n = cin.nextInt(); int…

zoj Fibonacci Numbers ( java , 简单，大数)

题目 //f(1) = 1, f(2) = 1, f(n > 2) = f(n - 1) + f(n - 2) import java.io.*; import java.util.*; import java.math.*; public class Main { /** * @xqq */ public BigInteger an(int n) { BigInteger c; BigInteger a = BigInteger.valueOf(1); BigInteger b = BigIn…

2017CCPC秦皇岛 G题Numbers&&ZOJ3987【大数】

题意: 给出一个数n,现在要将它分为m个数,这m个数相加起来必须等于n,并且要使得这m个数的或值最小. 思路: 从二进制的角度分析,如果这m个数中有一个数某一位为1,那么最后或起来这一位肯定是为1的,所以如果某一位为1了,那么我们尽量就让其余位也等于1.所以我们从最高位开始枚举,看看这一位是否需要为1,如果需要为1的话,那么剩下的几个数也尽量让这一位等于1. 代码: 不懂啊,还是看别人的代码写的,觉得有用就拿去吧.(卧槽,第一次开我的IDEA写java还不错的嘛) import java.mat…