Spreadsheets time limit per test 10 seconds memory limit per test 64 megabytes input standard input output standard output In the popular spreadsheets systems (for example, in Excel) the following numeration of columns is used. The first column has n…

 Exam time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output An exam for n students will take place in a long and narrow room, so the students will sit in a line in some order. The teacher suspect…

x86的指令集可分为以下4种: 通用指令 x87 FPU指令,浮点数运算的指令 SIMD指令,就是SSE指令 系统指令,写OS内核时使用的特殊指令 下面介绍一些通用的指令.指令由标识命令种类的助记符(mnemonic)和作为参数的操作数(operand)组成.例如move指令: 指令 操作数 描述 movq I/R/M,R/M 从一个内存位置复制1个双字(64位,8字节)大小的数据到另外一个内存位置 movl I/R/M,R/M 从一个内存位置复制1个字(32位,4字节)大小的数据到另外一个内存…

本文由HeapDump性能社区首席讲师鸠摩(马智)授权整理发布 第17章-x86-64寄存器 不同的CPU都能够解释的机器语言的体系称为指令集架构(ISA,Instruction Set Architecture),也可以称为指令集(instruction set).Intel将x86系列CPU之中的32位CPU指令集架构称为IA-32,IA是"Intel Architecture"的简称,也可以称为i386.x86-32.AMD等于Intell提出了x86系列的64位扩展,所以由AM…

B. Spreadsheets time limit per test 10 seconds memory limit per test 64 megabytes input standard input output standard output In the popular spreadsheets systems (for example, in Excel) the following numeration of columns is used. The first column ha…

[链接]:CF [题意]:对于一个数n,每次加一的代价是a,每次减一的代价是b,求被m整除时的最小代价. [分析]:分情况讨论,自己多举几个栗子. [代码]: #include<cstdio> #include<string> #include<cstdlib> #include<cmath> #include<iostream> #include<cstring> #include<set> #include<qu…

D. Mike and Feet time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Mike is the president of country What-The-Fatherland. There are n bears living in this country besides Mike. All of them are…

DNA Alignment time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Vasya became interested in bioinformatics. He's going to write an article about similar cyclic DNA sequences, so he invented a…

Amr and Pins time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Amr loves Geometry. One day he came up with a very interesting problem. Amr has a circle of radius r and center in point (x, y).…

Polycarpus' Dice time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Polycarp has n dice d1, d2, ..., dn. The i-th dice shows numbers from 1 to di. Polycarp rolled all the dice and the sum of n…

A and B and Team Training time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output A and B are preparing themselves for programming contests. An important part of preparing for a competition is shar…

题目链接:http://codeforces.com/problemset/problem/599/D 题意:定义F(n,m)为n行m列的矩阵中方阵的个数,比如3行5列的矩阵,3x3的方阵有3个.2x2的方阵有8个.1X1的方阵有15个,所以F(3,5)=3+8+15=26.现在告诉你F(a,b)=x中的x,要你求出所有满足要求的a,b,并按a递增的顺序输出. 思路:找出n行m列的矩阵中方阵数量的表达式即可,有些小细节需要注意... code: #include <iostream> #inc…

http://codeforces.com/contest/675/problem/C 题目大意: 给一个环,标号为1-n,然后能从n回到1.让这个环的值为0,最少需要的操作数是多少? 这道题目呀...应该说是自己的问题吧,规律并没有那么难找的,只要我将前缀全部都计算一遍就完全可以找出规律了的...然后竟然没有去那么做. 首先我们分析,最多的次数就是n-1.然后我们再看,因为是一个环,那么如果每次前缀和出现了0,就是说明这一段内可以得到0,那么所移动的次数就可以少1. 然后我们在反过来分析,我们…

In a far away galaxy there are n inhabited planets, numbered with numbers from 1 to n. They are located at large distances from each other, that's why the communication between them was very difficult until on the planet number 1 a hyperdrive was inv…

题意   Mishka想要去一个国家旅行,这个国家共有个城市,城市通过道路形成一个环,即第i个城市和第个城市之间有一条道路,此外城市和之间有一条道路.这个城市中有个首中心城市,中心城市与每个城市(除了自己)之间有一条道路.第城市个城市有一个魅力值,经过一条连接第个和第个城市的道路的费用是,求所有道路的费用之和是多少?   注意:任何两个城市之间最多只有一条路. 思路   先考虑所有中心城市:每条路只能算一遍,那么我们可以得到如下公式:   其中,代表所有城市的魅力值的和,代表已经计算过的中心城市…

NN is an experienced internet user and that means he spends a lot of time on the social media. Once he found the following image on the Net, which asked him to compare the sizes of inner circles: It turned out that the circles are equal. NN was very…

实在太冷了今天 taxi :错误原因1 忽略了 1 1 1 1 和 1 2 1 这种情况,直接认为最多两组一车了 2 语句顺序错 double cola: 忘了减去n的序号1,即n-- B. Taxi time limit per test 3 seconds memory limit per test 256 megabytes input standard input output standard output After the lessons n groups of schoolchi…

B. Friends and Presents time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You have two friends. You want to present each of them several positive integers. You want to present cnt1 numbers to…

The dragon and the princess are arguing about what to do on the New Year's Eve. The dragon suggests flying to the mountains to watch fairies dancing in the moonlight, while the princess thinks they should just go to bed early. They are desperate to c…

Ivan and Powers of Two time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Ivan has got an array of n non-negative integers a1, a2, ..., an. Ivan knows that the array is sorted in the non-decre…

B. Continued Fractions time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output A continued fraction of height n is a fraction of form . You are given two rational numbers, one is represented as  a…

题意:给n个元素,从n中选两个非空集合A和B.问有多少中选法? 递推: dp[n]表示元素个数为n的方案数,对于新来的一个元素,要么加入集合,要么不加入集合自成一个集合.加入集合有三种选择,A,B,E(可空的集合),或者自成集合,作为A或B,然后在选一个n-1个元素的非空子集(2^n-1 - 1). #include<cstdio> ; typedef unsigned long long ll; int main() { int n; scanf("%d",&n)…

http://codeforces.com/contest/602/problem/D 这题需要注意到的是,对于三个点(x1, y1)和(x2, y2)和(x3, y3).如果要算出区间[1, 3]的L(h)函数的最大值,则一定不会是 通过(y3 - y1) / (x3 - x1)算出.因为很简单,通过(x2, y2)作为辅助点,数值将会更加大. 然后设dis[i]表示abs(a[i + 1] - a[i]).那么区间[L, R]的最大值就是在dis[]中,[L, R - 1]数值的最大值. 因…

C. Sequence Transformation:http://codeforces.com/contest/1059/problem/C 题意 给你一个n,第一次输出1-n个数的gcd,然后你可以任意删除1-n中的数字,然后输出剩下n-1个数的gcd,再删一个数...,最后就是输出n个gcd值对吧. 要求输出的数列字典序最大. 思路 首先对于一个n,为了使得数列字典序最大,肯定是越早输出2越好,所以前面先把所有的奇数去掉,前(n+1)/2 个数肯定也就是1,那么剩下的偶数呢,可以先对这些偶…

E. Jzzhu and Apples time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Jzzhu has picked n apples from his big apple tree. All the apples are numbered from 1 to n. Now he wants to sell them to…

ACM思维题训练集合 To confuse the opponents, the Galactic Empire represents fractions in an unusual format. The fractions are represented as two sets of integers. The product of numbers from the first set gives the fraction numerator, the product of numbers…

LINK:Quantifier Question 题面过长 引起不适 读题花了好长时间 对于 和 存在符合不是很熟练 导致很懵逼的做完了. 好在还算很好想.不过wa到了一个坑点上面 自闭一大晌 还以为自己思路错了 看了某个强者的blog才知道自己有个地方没处理好. 题目中明确指出 这种关系运算符只能顺序的添加 也就是说 \(\forall x_2\exists x_1\) 这是不能被表达的 只能表达出\(\exists x_1\forall x_2\) 如果有题目中的f函数 那么后者将会被判定为…

题意: m个水果,n个价格.每种水果只有一个价格. 问如果给每种水果分配价格,使得买的m个水果总价格最小.最大. 输出最小值和最大值. 思路: 贪心. 代码: bool cmp(int a,int b){ return a>b; } string name; map<string,int> mp; int price[200],fruit[200]; int cn; int n,m; int main(){ cin>>n>>m; mp.clear(); cn=0;…

题意: 给一个数X. 起始点为坐标0.第1步跳1格,第2步跳2格,第3步跳3格,.....以此类推. 每次可以向左跳或向右跳. 问最少跳几步可以到坐标X. 思路: 假设X是正数. 最快逼近X的方法是不停向右走.如果越过了X,假设到了X1,则必有X1-X小于最后一步d. 如果X1-X是偶数,将之前的某个x变为-x.则可以到X. 如果X1-X是奇数,因为将之前的某个x变为-x,实际是后退2x格.所以必定要再向右走一步.直到X1-X是偶数.(其实只要走一步或两步) X是负数的情况和X是正数的情况一样.…

 cf之路,1,Codeforces Round #345 (Div. 2) ps:昨天第一次参加cf比赛,比赛之前为了熟悉下cf比赛题目的难度.所以做了round#345连试试水的深浅.....       其实这个应该是昨天就写完的,不过没时间了,就留到了今天.. 地址:http://codeforces.com/contest/651/problem/A A. Joysticks time limit per test 1 second memory limit per test 256…