题目: 求一个数组的最长递减子序列比 , 如随机生成一组序列 {8,9,6,3,6,2,3,4}   求得最长递减序列 {9,8,6,4,3,2} list=[3,3,3,3,6,2,3,4] //冒泡排序 n=len(list) for i in range(0,n-2): for k in range(0,n-1): if list[k+1]>list[k]: list[k+1],list[k]=list[k],list[k+1] print(list) result=[] for i in…

题目链接 Problem Description We are all familiar with sorting algorithms: quick sort, merge sort, heap sort, insertion sort, selection sort, bubble sort, etc. But sometimes it is an overkill to use these algorithms for an almost sorted array. We say an a…

6357. Hills And Valleys 自己感觉这是个好题,应该是经典题目,所以半路选手补了这道字符串的动态规划题目. 题意就是给你一个串,翻转任意区间一次,求最长的非下降子序列. 一看题面写的0≤Ai≤9 (i=1,2,⋯,n).就知道肯定有点东西,只要这么写,肯定就是有某个神奇的操作可以解决这道题目. 比赛的时候脑壳都要炸了也没想出来,补题的时候懂了,我可以定义一个b串为0123456789,这肯定是递增的,所以我翻转b的某个区间,然后去和a匹配,因为我把b再翻转回来,还是递增的.…

                                                                              D. Once Again... You are given an array of positive integers a1, a2, ..., an × T of length n × T. We know that for any i > n it is true that ai = ai - n. Find the length of…

题意:给一串由n个数字组成的字符串,选择其中一个区间进行翻转,要求翻转后该字符串的最长非降子序列长度最长,输出这个最长非降子序列的长度以及翻转的区间的左右端点 #include<bits/stdc++.h> using namespace std; typedef long long ll; ; ; int n, a[maxn], dp[maxn][maxm], b[maxm]; int ans, ansl, ansr, l, r, cnt; int al[maxn][maxm], ar[ma…

Constructing Roads In JGShining's Kingdom Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 27358    Accepted Submission(s): 7782 Problem Description JGShining's kingdom consists of 2n(n is no mor…

A B C 给你一个长度为N的01串 你可以翻转一次任意[L,R]的区间 问你最长的不递减序列为多少长 处理出1的前缀和 和2的后缀和 然后N^2 DP 处理出 [L,R]区间的最长不递增序列 #include <bits/stdc++.h> #define PI acos(-1.0) #define mem(a,b) memset((a),b,sizeof(a)) #define TS printf("!!!\n") #define pb push_back #defin…

A. Kefa and First Steps time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Kefa decided to make some money doing business on the Internet for exactly n days. He knows that on the i-th day (1 …

最长递减子序列(nlogn): int find(int n,int key) { ; int right=n; while(left<=right) { ; if(res[mid]>key) { left=mid+; } else { right=mid-; } } return left; } int Lis(int a[],int n) { ; res[r]=a[]; r++; ;i<n;i++) { ]>a[i]) { res[r]=a[i]; r++; } else {…

A person wants to travel around some places. The welfare in his company can cover some of the airfare cost. In order to control cost, the company requires that he must submit the plane tickets in time order and the amount of the each submittal must b…