HDU 3642 扫描线（立方体体积并）

【HDU 3642 扫描线（立方体体积并）】的更多相关文章

HDU 3642 扫描线（立方体体积并）

Get The Treasury Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2190 Accepted Submission(s): 669 Problem Description Jack knows that there is a great underground treasury in a secret region…

HDU 3255 扫描线（立方体体积并变形）

Farming Time Limit: 12000/6000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1375 Accepted Submission(s): 402 Problem Description You have a big farm, and you want to grow vegetables in it. You're too lazy to se…

hdu 3642 Get The Treasury(扫描线)

pid=3642" style="">题目链接:hdu 3642 Get The Treasury 题目大意:三维坐标系,给定若干的长方体,问说有多少位置被覆盖3次以上. 解题思路:扫描线,将第三维分离出来,就是普通的二维扫描线,然后对于每一个节点要维护覆盖0,1,2.3以上这4种的覆盖面积. #include <cstdio> #include <cstring> #include <vector> #include <alg…

Get The Treasury HDU - 3642（体积扫描线）

给出n个立方体,要你求这些立方体至少被覆盖三次的部分. 先把这个立方体的信息存在来,发现Z的范围不大,z范围是是[-500,500],所以我们可以先离散化,然后枚举Z, 然后对于每一段Z的区域内,在当前的区域内对xoy轴使用一次扫描线,找到当前这个区域内被覆盖三次的体积,然后每次枚举Z,每次相加,就是最后的答案. #include<map> #include<set> #include<ctime> #include<cmath> #include<s…

Get The Treasury HDU - 3642（扫描线求三维面积交。。体积交）

题意: ...就是求体积交... 解析: 把每一层z抽出来,计算面积交, 然后加起来即可..! 去看一下二维面积交的代码再看看这个三维面积交的代码.. down函数里你发现了什么规律!!! 参考二维面积交:https://www.cnblogs.com/WTSRUVF/p/9274318.html 代码如下 #include <cstdio> #include <iostream> #include <cstring> #include <algorithm…

HDU 3642 - Get The Treasury - [加强版扫描线+线段树]

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3642 Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description Jack knows that there is a great underground treasury in a secret region. And he has a special d…