leetcode-4. 寻找两个正序数组的中位数. 给定两个大小为 m 和 n 的正序(从小到大)数组 nums1 和 nums2. 请你找出这两个正序数组的中位数,并且要求算法的时间复杂度为 O(log(m + n)). 你可以假设 nums1 和 nums2 不会同时为空. 示例 1: nums1 = [1, 3] nums2 = [2] 则中位数是 2.0 示例 2: nums1 = [1, 2] nums2 = [3, 4] 则中位数是 (2 + 3)/2 = 2.5 来源:力扣(Lee…

There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). Example 1: nums1 = [1, 3] nums2 = [2] The median is 2.0 Example 2: nums1 = [1,…

题目: You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 -&…

题目: There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).   (Hard) Example 1: nums1 = [1, 3] nums2 = [2] The median is 2.0 Example 2…

Valid Palindrome回文数 whowhoha@outlook.com Question: Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. For example, "A man, a plan, a canal: Panama" is a palindrome. "race a car"…

这道题目和PAT上的1029是同一题.但是PAT1029用O(m+n)的时间复杂度(题解)就可以,这道题要求是O(log(m+n)). 这道题花费了我一个工作日的时间来思考.因为是log因而一直思考如何进行二分,想着是两个vector分别二分,但一直想不到合适的解法,就是无穷尽的if else 后来看了题解.思路是从两个有序数组中寻找第k小的数. <1>花了很长时间在调试上,结果发现是少了一个return,期间还不停怀疑自己写递归的能力...要被自己打败了,调代码真是一件细小却很耗费心神的事情…

链接:https://leetcode-cn.com/problems/median-of-two-sorted-arrays/description/ 有两个大小为 m 和 n 的排序数组 nums1 和 nums2 . 请找出两个排序数组的中位数并且总的运行时间复杂度为 O(log (m+n)) . 示例 1: nums1 = [, ] nums2 = [] 中位数是 2.0 示例 2: nums1 = [, ] nums2 = [, ] 中位数是 (2 + 3)/2 = 2.5 分析 这道…

There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)). You may assume nums1 and nums2 cannot be both empty. Example 1: nums1 = [1, 3]…

给定两个大小为 m 和 n 的有序数组 nums1 和 nums2 . 请找出这两个有序数组的中位数.要求算法的时间复杂度为 O(log (m+n)) . 1.我的思路:直接用sort,时间复杂度应如图所示 class Solution: def findMedianSortedArrays(self, nums1, nums2): """ :type nums1: List[int] :type nums2: List[int] :rtype: float "&q…

public class Solution { public double FindMedianSortedArrays(int[] nums1, int[] nums2) { var nums = nums1.Concat(nums2).OrderBy(x => x).ToArray(); var len = nums.Length; == ) { ] + nums[len / - ]) / ; } else { ]); } } }…