Leetcode:Minimus Depth of Binary Tree】的更多相关文章

The problem description: Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 这个题目本身不是很难,二叉树的广搜找到最浅的那个子树.但这个题目是比较典型的再广搜的时候需要记录或者使用到当前深度信息,所以我们需…
LeetCode:Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 算法1:dfs递归的求解 class Solution { public: int minDepth(T…
LeetCode--Maximum Depth of Binary Tree Question Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Answer /** * Definition for a binary tree…
Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 二叉树的经典问题之最小深度问题就是就最短路径的节点个数,还是用深度优先搜索DFS来完成,万能的递归啊...请看代码: /** * Definition for binary tre…
Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 求二叉树的最大深度问题用到深度优先搜索DFS,递归的完美应用,跟求二叉树的最小深度问题原理相同.代码如下: C++ 解法一: class Solution { public: in…
Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. SOLUTION 1: 递归 这种递归解法更简单.因为在本层递归中不需要考虑左右子树是否为NULL的情况.因为我们直接把…
题目: Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 思路: 递归,注意是到leaf node,所以有一个孩子为空的话,则取非空的那一孩子 package tree; public class MinimumDepthOfBi…
Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 递归求解 int maxDepth(TreeNode *root){ +max(maxDepth(root->left), maxDepth(root->right)) : ;…
Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. 方法一: 层次遍历,整棵树的层数,即二叉树的最大深度.主体的代码还是在层次遍历的基础上改成的. /** * Definition for binary tree * struct…
Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Hide Tags Tree Depth-first Search     简单的深度搜索 #include <iostream> using namespace std; /*…
Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. Hide Tags Tree Depth-first Search       这题是找二叉树的最小深度,这是广度搜索比较好吧,为啥提示给的是 深度优先呢. 判断树是否为空 将ro…
https://oj.leetcode.com/problems/maximum-depth-of-binary-tree/ 求二叉树的最大深度 深度优先搜索 /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class…
题意:给一棵二叉树,求其深度. 思路:递归比较简洁,先求左子树深度,再求右子树深度,比较其结果,返回:max_one+1. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution {…
# Definition for a binary tree node. # class TreeNode(object): # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution(object): def maxDepth(self, root): """ :type root: TreeNode :rtype: int ""…
# Definition for a binary tree node. # class TreeNode(object): # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution(object): def minDepth(self, root): """ :type root: TreeNode :rtype: int ""…
1.类中递归调用添加self: 2.root为None,返回0 3.root不为None,root左右孩子为None,返回1 4.返回l和r最小深度,l和r初始为极大值: # Definition for a binary tree node # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: # @param root,…
# Definition for a binary tree node # class TreeNode: # def __init__(self, x): # self.val = x # self.left = None # self.right = None class Solution: # @param root, a tree node # @return an integer def maxDepth(self, root): if root == None: return 0 l…
题意:找到离根结点最近的叶子结点的那一层(设同一层上的结点与根结点的距离相等),返回它所在的层数. 方法有: 1.递归深度搜索 2.层次搜索 方法一:递归(无优化) /** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ cla…
第五道树题,10分钟之内一遍AC.做树题越来越有feel~ 题目:求一棵树从root结点到叶子结点的最短路径. 思路:仍然是递归.如果一个结点的左右子树任意一边为Null,该子树的minDepth应为非null子树的高度+1:如果一个结点的左右子树两边都非Null,则该子树的minDepth应为两个子树的较小值 代码: public int minDepth(TreeNode root) { if(root == null) return 0; if(root.left == null &&…
第三道树的题目,我还是不会,我擦,怎么递归算法还是不能很好理解.看来还得好好研究下递归算法. 题目:求一棵树的最大深度. 思路:递归地求取左子树最大深度 和 右子树最大深度,返回较大值即为 整棵树的 最大深度. 代码: public int maxDepth(TreeNode root) { if(root == null) return 0; int leftHeight = 1,rightHeight = 1; if(root.left != null) leftHeight += maxD…
LeetCode:Maximum Depth of Binary Tree [问题再现] Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. [优质算法] 算法一: public class Solution { public in…
[LeetCode]Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 递归和非递归,此提比较简单.广度优先遍历即可.关键之处就在于如何保持访问深度. 下面是4种代码: im…
[Leetcode] Maximum and Minimum Depth of Binary Tree 二叉树的最小最大深度 (最小有3种解法) 描述 解析 递归深度优先搜索 当求最大深度时,我们只要在左右子树中取较大的就行了. 然而最小深度时,如果左右子树中有一个为空会返回0,这时我们是不能算做有效深度的. 所以分成了三种情况,左子树为空,右子树为空,左右子树都不为空.当然,如果左右子树都为空的话,就会返回1. 广度优先搜索(类似层序遍历的思想) 递归解法本质是深度优先搜索,但因为我们是求最小…
    题目URL:https://leetcode.com/problems/minimum-depth-of-binary-tree/ 111. Minimum Depth of Binary Tree My Submissions Question Total Accepted: 94580 Total Submissions: 312802 Difficulty: Easy Given a binary tree, find its minimum depth. The minimum…
Given a binary tree, find its maximum depth. The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. Note: A leaf is a node with no children. Example: Given binary tree [3,9,20,null,null,15,7…
Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 给一个二叉树,找出它的最小深度.最小深度是从根节点向下到最近的叶节点的最短路径,就是最短路径的节点个数. 解法1:DFS 解法2: BFS Java: DFS, Time Comp…
104. 二叉树的最大深度 104. Maximum Depth of Binary Tree 题目描述 给定一个二叉树,找出其最大深度. 二叉树的深度为根节点到最远叶子节点的最长路径上的节点数. 说明: 叶子节点是指没有子节点的节点. LeetCode104. Maximum Depth of Binary Tree 示例: 给定二叉树 [3,9,20,null,null,15,7], 3 / \ 9 20 / \ 15 7 返回它的最大深度 3. Java 实现 class TreeNode…
Minimum Depth of Binary Tree Given a binary tree, find its minimum depth. The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node. 比较左子树和右子树的深度,取小的那个返回上来,并+1. 需要注意的是如果没有左子树或右子树.那么无条件取存在的那一边子树深…
Same Tree Given two binary trees, write a function to check if they are equal or not. Two binary trees are considered equal if they are structurally identical and the nodes have the same value. Maximum Depth of Binary Tree Given a binary tree, find i…
找出最短的从叶子到根的路径长 可以回忆Maximum Depth of Binary Tree的写法,只不过在!root,我把它改成了10000000,还有max函数改成了min函数,最后的值如果是10000000,毫无疑问这棵树肯定为空,因此在最后有(d>=1000000)?0:d; /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *righ…