1251. Cemetery Manager Time limit: 1.0 secondMemory limit: 64 MB There is a tradition at the USU championships to call the most hard-to-solve problems coffins. But to distribute coffins is also a very difficult problem. Consider a cemetery with place…
Building #11 is undergoing a major renovation. Implement a query to close all requests from apartments in this building. -- TABLE Apartments +-------+------------+------------+ | AptID | UnitNumber | BuildingID | +-------+------------+------------+ |…
Write a SQL query to get a list of all buildings and the number of open requests (Requests in which status equals 'Open'). -- TABLE Apartments +-------+------------+------------+ | AptID | UnitNumber | BuildingID | +-------+------------+------------+…
Write a SQL query to get a list of tenants who are renting more than one apartment. -- TABLE Apartments +-------+------------+------------+ | AptID | UnitNumber | BuildingID | +-------+------------+------------+ | 101 | A1 | 11 | | 102 | A2 | 12 | |…
ref:http://bash.cyberciti.biz/guide/Getting_User_Input_Via_Keyboard You can accept input from the keyboard and assign an input value to a user defined shell variable using read command. Contents 1 read Command Syntax 1.1 Handling Input 1.2 Examples 1…
Description FatMouse prepared M pounds of cat food, ready to trade with the cats guarding the warehouse containing his favorite food, JavaBean. The warehouse has N rooms. The i-th room contains J[i] pounds of JavaBeans and requires F[i] pounds of ca…
Longest Ordered Subsequence Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 32192 Accepted: 14093 Description A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence (a1, a2, ...…
题目大意:使用两个哈希表来解决哈希冲突的问题.假如现在有两个哈希表分别为:H1,H2 ,大小分别为:n1,n2:现有一数据X需要插入,其插入方法为: 1.计算index1 = X MOD N1, 若哈希表H1的index1位置没有保存数据,则直接将X保存到H1得index1:否则,若哈希表H1的index1位置已经保存有数据X1,则将原来已保存的数据X1进行缓存,然后将X插入H1的index1的位置. 2.将上一步缓存的X1插入到哈希表H2,首先计算index2=X1 MOD N2,若H2的i…
[Python] 零碎知识积累 II ■ 函数的参数默认值在函数定义时确定并保存在内存中,调用函数时不会在内存中新开辟一块空间然后用参数默认值重新赋值,而是单纯地引用这个参数原来的地址.这就带来了一个坑,那就是当你在函数体中对默认参数做一些改变的时候,若参数默认值是int,str这种不可变类型,那么还好,因为默认参数在内存中并没改变,只是参数指向另一块空间:但若是list这种可变类型,当你对默认参数做改变的时候,将会直接影响这个参数在内存中实际的值,这也就影响了下次调用这个函数时参数的默认值.比…
Unlike in nowadays, the way that boys and girls expressing their feelings of love was quite subtle in the early years. When a boy A had a crush on a girl B, he would usually not contact her directly in the first place. Instead, he might ask another b…
Unlike in nowadays, the way that boys and girls expressing their feelings of love was quite subtle in the early years. When a boy A had a crush on a girl B, he would usually not contact her directly in the first place. Instead, he might ask another b…
1139 First Contact(30 分) Unlike in nowadays, the way that boys and girls expressing their feelings of love was quite subtle in the early years. When a boy A had a crush on a girl B, he would usually not contact her directly in the first place. Instea…
